谁能帮我完成这个 python-if-else 任务？

Question

import randomn = random.randint(1,100)if (n % 2 != 0):    print("Weird")elif (n % 2 == 0 and n in range(2,5)):    print("Not Weird")elif (n % 2 == 0 and n in range(6,20)):    print("Weird")elif (n % 2 == 0 and n > 20):    print("Not Weird")    这段代码有问题吗？

Answer 1

您的范围检查并不严格，例如：包括andrange(2, 5)之间的整数，但无论如何有一种更简单的方法来编写它；尝试这个：24

import random    

n = random.randint(1,100)

if n % 2 != 0:

    print("Weird")

elif 2 <= n <= 5: # from this point on, the number can only be even

    print("Not Weird")

elif 6 <= n <= 20:

    print("Weird")

elif n > 20:

    print("Not Weird")

或者更好的是，它更简单并且做同样的事情：

if n % 2 != 0 or 6 <= n <= 20:

    print("Weird")

else:

    print("Not Weird")

Answer 2

随机导入

n = random.randint(1,100)

print(n)

if (n % 2 != 0):

    print("Weird")

elif (n % 2 == 0 and n in range(2,5)):

    print("Not Weird")

elif (n % 2 == 0 and n in range(5,20)):

    print("Weird")

elif (n % 2 == 0 and n >= 20):

    print("Not Weird")

您缺少一些范围，我刚刚更新了代码尝试一下。