如何让这个 php 代码连接到 sql 工作台？

Question

我在使用 pdo 连接到 Sql Workbench 时遇到问题。显示以下错误，尽管我已经尝试了各种连接方式。收到错误：SQLSTATE [HY000] [1045] 用户'root'@'localhost'的访问被拒绝（使用密码：否）<?phpsession_start();try {$con = new PDO ("mysql:host=localhost;dbname=users",'root','');if(isset($_POST['signup'])){    $username = $_POST['username'];    $email = $_POST['email'];    $password = $_POST['password'];    $fname = $_POST['fname'];    $lname = $_POST['lname'];    $city = $_POST['city'];    $insert = $con->prepare("INSERT INTO users1(username,email,password,fname,lname,city)            values(:username, :email, :password, :fname, :lname, :city)            ");    $insert->bindParam (':username',$username);    $insert->bindParam (':email',$email);    $insert->bindParam (':password',$password);    $insert->bindParam (':fname',$fname);    $insert->bindParam (':lname',$lname);    $insert->bindParam (':city',$city);    $insert->execute();}elseif (isset($_POST['signin'])){    $username = $_POST['username'];    $password = $_POST['password'];    $select = $con->prepare("SELECT*FROM users1 where username='$username' and password='$password'");    $select->setFetchMode(PDO::FETCH_ASSOC);    $select->execute();    $data=$select->fetch();    if($data['username']!=$username and $data['password']!=$password)    {        echo "Invalid username or Password";    }    elseif($data['username']==$username and $data['password']==$password)    {        $_SESSION['username']=$data['username'];        $_SESSION['email']=$data['email'];        $_SESSION['fname']=$data['fname'];        $_SESSION['lname']=$data['lname'];        header("location:profile.php");    }     }}catch (PDOException $e) {       echo "Error: ". $e -> getMessage();}?>

Answer 1

如果您不知道密码，可以使用以下命令更新密码：

UPDATE mysql.user SET Password=PASSWORD('MyNewPass') WHERE User='root';

//then connection will be:

$con = new PDO ("mysql:host=localhost;dbname=users",'root','MyNewPass');

Answer 2

我认为它要求输入密码

 $con = new PDO ("mysql:host=localhost;dbname=users",'root','your_password');