如何处理 ZipException（文件密码错误：Demo.zip）并显示适当的消息

Question

    由于我是 Java 新手，我创建了一种解压缩受密码保护的 zip 文件的方法，我使用 zip4j 库来解压缩 zip 文件，密码正确时代码工作正常，但密码错误时如何处理ZipException（net.lingala.zip4j.exception.ZipException：net.lingala.zip4j.exception.ZipException：net.lingala.zip4j.exception.ZipException：文件密码错误：Demo.zip）并显示适当的消息（密码错误！ ）。请帮助，这是我的代码。import net.lingala.zip4j.core.ZipFile;import net.lingala.zip4j.exception.ZipException;import net.lingala.zip4j.model.ZipParameters;import net.lingala.zip4j.util.Zip4jConstants;public class UnunzipDemo{    public void unzipFilesWithPassword(String sourceZipFilePath,String extractedZipFilePath,String password){        try {            ZipFile zipFile = new ZipFile(sourceZipFilePath);            if (zipFile.isEncrypted()) {                zipFile.setPassword(password);            }            zipFile.extractAll(extractedZipFilePath);            System.out.println("Done");        }        catch (ZipException e) {            e.printStackTrace();        }    }    public static void main(String[] args) {        String sourceZipFilePath="E:/MyFiles/Files/Zip/Demo.zip";        String extractedZipFilePath="E:/MyFiles/Files/Unzip/";        String password="JOEL"; //Correct Password        UnunzipDemo unzipDemo=new UnunzipDemo();        unzipDemo.unzipFilesWithPassword(sourceZipFilePath,extractedZipFilePath,password);    }}

Answer 1

也许您可以从控制台读取密码。例如：

    private static String password = "123";

    public static void main(String[] args) {

        // read the input password from console

        // if you have UI, maybe you can read it from some way.

        Scanner sc = new Scanner(System.in);

        String inputPassword = sc.next();

        while (true) {

            //do something...

            try {

                unzip(inputPassword);

                break;

            } catch (Exception e) {

                inputPassword = sc.next();

            }

        }

    }

    private static void unzip(String inputPassword) {

        if (inputPassword.equals(password)) {

            //unzip

        } else {

            // just demo. In your case, this is ZipException

            throw new IllegalArgumentException("wrong password");

        }

    }

Answer 2

您还可以检查错误代码。

public void unzipFilesWithPassword(String sourceZipFilePath,String extractedZipFilePath,String password){

    try {

        ZipFile zipFile = new ZipFile(sourceZipFilePath);

        if (zipFile.isEncrypted()) {

            zipFile.setPassword(password);

        }

        zipFile.extractAll(extractedZipFilePath);

        System.out.println("Done");

    }

    catch (ZipException e) {

        if (e.getCode == ZipExceptionConstants.WRONG_PASSWORD) {

           // Handle wrong password scenario

           System.out.println("Wrong password");

        } else {

           //Handle other exception scenario - printing out error messages?

        }

    }