为什么结构副本上的更改会反映 go 中的原始结构？

Question

我对 Go 中的按值传递感到困惑。我正在这样做；package mainimport (    "fmt")type point struct {    x    int    list []int}func main() {    p := point{20, []int{1, 2, 3, 4, 5}}    fmt.Printf("Address: %p, Value: %v\n", &p, p)    passByValue(p, 1)    fmt.Printf("Address: %p, Value: %v\n", &p, p)}func passByValue(copyOfP point, i int) {    copyOfP.list = append(copyOfP.list[:i], copyOfP.list[i+1:]...)    fmt.Printf("From passByValue Address: %p, Value: %v\n", &copyOfP, copyOfP)}输出：Original p Address: 0xc00000c080, Value: {20 [1 2 3 4 5]}passByValue copyOfP Address: 0xc00000c0c0, Value: {20 [1 3 4 5]}Original p Address: 0xc00000c080, Value: {20 [1 3 4 5 5]}不copyOfP应该是副本，p也不应该反映原来p的东西。这里发生了什么事？

Answer 1

func main() {

    // history.ReadlineTest()

    p := point{20, []int{1, 2, 3, 4, 5}}

    fmt.Printf("Address: %p, Value: %v\n", &p.list[0], p)

    passByValue(p, 1)

    fmt.Printf("Address: %p, Value: %v\n", &p.list[0], p)

}

func passByValue(copyOfP point, i int) {

    copyOfP.list = append(copyOfP.list[:i], copyOfP.list[i+1:]...)

    fmt.Printf("From passByValue Address: %p, Value: %v\n", &copyOfP.list[0], copyOfP)

}

Address: 0xc00001a0c0, Value: {20 [1 2 3 4 5]}

From passByValue Address: 0xc00001a0c0, Value: {20 [1 3 4 5]}

Address: 0xc00001a0c0, Value: {20 [1 3 4 5 5]}

“列表”切片重用了相同的内存。