随便输入范围内的数字，结果报错说if not num_input.isdight():？

Question

#!/usr/bin/env python#coding:UTF-8import randomnumber = random.randint(1,101)guess=0while True:num_input =input("please input one integer that is 1 to 100:")guess += 1if not num_input.isdight():print("please input interger")elif int(num_input) < 0 or int(num_input) >= 100:print("the number should be in 1 to 100")else:if number==int(num_input):print("you are right")breakelif number > int(num_input):print("your number is more less")elif number < int(num_input):print("your number is more bigger")else:print("I will not work")我运行随便输入范围内的数字 结果报错说if not num_input.isdight():AttributeError: 'str' object has no attribute 'isdight' 怎么回事 谢谢了

Answer 1

#!/usr/bin/env python#coding:UTF-8  import randomnumber=random.randint(1,101)guess=0while True:      num_input=raw_input("please input one integer that is 1 to 100:")    guess+=1      if not num_input.isdigit():#是isdigit        print("please input interger")    elif int(num_input)< 0 or int(num_input)>= 100:        print("the number should be in 1 to 100")    else:        if number==int(num_input):            print("you are right")            break        elif number>int(num_input):            print("your number is more less")        elif number<int(num_input):            print("your number is more bigger")        else:                     print("I will not work")