如何使用 html 模板解组结构？

Question

我正在尝试将 JSON 解组到我的 Mail 结构，但 Go 在解析 html_tmpl 和 text_tmpl 字段时返回错误。我怎么解决这个问题？HtmlTmpl 字段来自：html, err := template.ParseFiles(pathToHTMLFile)这是您可以测试的基本示例package mainimport (    "encoding/json"    "fmt"    "html/template"    "time")type Mail struct {    Id       string            `json:"id"`    Subject  string            `json:"subject"`    From     string            `json:"from"`    To       string            `json:"to"`    Date     time.Time         `json:"date"`    HtmlTmpl template.Template `json:"html_tmpl"`    TextTmpl template.Template `json:"text_tmpl"`    Context  map[string]string `json:"context"`}func main() {  mail := &Mail{}  s := `{"id":"","subject":"Test mail","from":"[e-mail]","to":"[e-mail]","date":"0001-01-01T00:00:00Z","html_tmpl":{"Tree":{"Name":"template.html","ParseName":"template.html","Root":{"NodeType":11,"Pos":0,"Nodes":[{"NodeType":0,"Pos":0,"Text":"PCFET0NUWVBFIGh0bWw+CjxodG1sIGxhbmc9InJ1Ij4KPGhlYWQ+Cgk8bWV0YSBodHRwLWVxdWl2PSJDb250ZW50LVR5cGUiIGNvbnRlbnQ9InRleHQvaHRtbCIgY2hhcnNldD0iVVRGLTgiPgoJPG1ldGEgbmFtZT0idmlld3BvcnQiIGNvbnRlbnQ9IndpZHRoPWRldmljZS13aWR0aCwgaW5pdGlhbD0xIj4KCTxtZXRhIGh0dHAtZXF1aXY9IlgtVUEtQ29tcGF0aWJsZSIgY29udGVudD0iSUU9ZWRnZSI+Cgk8dGl0bGU+0J/RgNC+0LLQtdGA0LrQsCDRgdCy0Y/Qt9C4PC90aXRsZT4KPC9oZWFkPgo8Ym9keT4KCTxzcGFuPg=="},{"NodeType":1,"Pos":298,"Line":10,"Pipe":{"NodeType":14,"Pos":298,"Line":10,"IsAssign":false,"Decl":null,"Cmds":[{"NodeType":4,"Pos":298,"Args":[{"NodeType":8,"Pos":298,"Ident":["msg"]}]}]}},{"NodeType":0,"Pos":305,"Text":"PC9zcGFuPgo8L2JvZHk+CjwvaHRtbD4="}]}}},"text_tmpl":{"Tree":{"Name":"template.txt","ParseName":"template.txt","Root":{"NodeType":11,"Pos":0,"Nodes":[{"NodeType":1,"Pos":2,"Line":1,"Pipe":{"NodeType":14,"Pos":2,"Line":1,"IsAssign":false,"Decl":null,"Cmds":[{"NodeType":4,"Pos":2,"Args":[{"NodeType":8,"Pos":2,"Ident":["msg"]}]}]}}]}}},"context":{"msg":"Hi!"}}`  err := json.Unmarshal([]byte(s), mail)  fmt.Println(err)  fmt.Println(mail)}

Answer 1

template.Template不支持从 JSON 编组/解组。它是一个带有未导出字段的结构，并且它没有实现处理封送/解封逻辑的接口（例如json.Unmarshaler）。

您应该做的是在您的 JSON 和结构中包含源模板文本，并在解组源模板文本后，将其解析为后处理步骤。如果你想编组一个包含模板的结构，它应该只包含源模板文本（template.Template字段应该被标记为省略，如json:"-"）。