你好，在C语言中有没有把字符串拆分为数组的函数？如果有，请问是？

Question

张三$|男$|济南$|大专学历$|如上是一个字符串， 把上面的字符串按 $| 分成一个数组。如：myArray[0] = "张三";myArray[1] = "男";myArray[2] = "济南";myArray[3] = "大专学历";C语言有没有提供相关函数啊？ 如果没有能帮我写一个吗，谢谢。要求能支持中文的。

Answer 1

直接用简单的C++

#include <iostream>#include <string>#include <vector>using namespace std; //把字符串s按照字符串c进行切分得到vector_v vector<string> split(const string& s, const string& c){    vector<string> v;    int pos1=0,pos2;    while((pos2=s.find(c,pos1))!=-1){        v.push_back(s.substr(pos1, pos2-pos1));        pos1 = pos2 + c.size();      }    if(pos1 != s.length())        v.push_back(s.substr(pos1));    return v; }  int main(){    string input="张三$|男$|济南$|大专学历$|";    vector<string>  myArray=split(input,"$|");    for(int i=0;i<myArray.size();i++){        cout<<myArray[i]<<endl;    }}/*张三男济南大专学历*/

Answer 2

用strtok函数实现吧。
void split( char **arr, char *str, const char *del)//字符分割函数的简单定义和实现
{
char *s =NULL;

s=strtok(str,del);
while(s != NULL)
{
*arr++ = s;
s = strtok(NULL,del);
}
}

int main()
{
int i;
char *myArray[4];
char s[] = "张三$|男$|济南$|大专学历$|";

memset(myArray, 0x0, sizeof(myArray));
split(myArray, s, "$|");

for (i=0; i<4; i++)
{
printf("%s\n", myArray[i]);
}
return 0;
}

Answer 3

char str[] = "now $| is the time for all $| good men to come to the $| aid of their country";
char delims[] = "$|";
char *result = NULL;

result = strtok( str, delims );

while( result != NULL )
{
printf( "result is \"%s\"\n", result );
result = strtok( NULL, delims );
}
以上代码的运行结果是：

result is "now "
result is " is the time for all "
result is " good men to come to the "
result is " aid of their country"