将值分配给列表的最短代码

Question

什么可能是最短的代码：public void update(final Product object, final Callback<Product> callback) {    if(object.getIsDayDependent()) {        Double priceDay0 = object.getSundayPrice();        Double priceDay1 = object.getMondayPrice();        Double priceDay2 = object.getTuesdayPrice();        Double priceDay3 = object.getWednesdayPrice();        Double priceDay4 = object.getThursdayPrice();        Double priceDay5 = object.getFridayPrice();        Double priceDay6 = object.getSaturdayPrice();        List<DayPrice> dayPrices = new LinkedList<>();        dayPrices.add(new DayPrice(0, priceDay0));        dayPrices.add(new DayPrice(1, priceDay1));        dayPrices.add(new DayPrice(2, priceDay2));        dayPrices.add(new DayPrice(3, priceDay3));        dayPrices.add(new DayPrice(4, priceDay4));        dayPrices.add(new DayPrice(5, priceDay5));        dayPrices.add(new DayPrice(6, priceDay6));        object.setDayDependent(dayPrices);    } else {        object.setPrice(null);        object.setDayDependent(new LinkedList<>());    }    callback.onSuccess(object);}

Answer 1

下面的代码并没有像减少语句数量那样最小化代码，但它也消除了不必要的变量：

if(object.getIsDayDependent()) {

    List<Double> prices = Arrays.asList(object.getSundayPrice(),

            object.getMondayPrice(),

            object.getTuesdayPrice(),

            object.getWednesdayPrice(),

            object.getThursdayPrice(),

            object.getFridayPrice(),

            object.getSaturdayPrice());

    object.setDayDependent(IntStream.range(0, 7)

            .mapToObj(i -> new DayPrice(i, prices.get(i)))

            .collect(Collectors.toCollection(LinkedList<Double>::new)));

} else {

    object.setPrice(null);

    object.setDayDependent(new LinkedList<>());

}

Answer 2

在不修改关联类（产品类）作为挑战的情况下，我为此拥有的最短代码是这样的：

        if(object.getIsDayDependent())) {

            Double priceDay0 = object.getSundayPrice();

            Double priceDay1 = object.getMondayPrice();

            Double priceDay2 = object.getTuesdayPrice();

            Double priceDay3 = object.getWednesdayPrice();

            Double priceDay4 = object.getThursdayPrice();

            Double priceDay5 = object.getFridayPrice();

            Double priceDay6 = object.getSaturdayPrice();

            object.setDayDependent(new LinkedList<>(Arrays.asList(

                    new DayPrice(0, priceDay0),

                    new DayPrice(1, priceDay1),

                    new DayPrice(2, priceDay2),

                    new DayPrice(3, priceDay3),

                    new DayPrice(4, priceDay4),

                    new DayPrice(5, priceDay5),

                    new DayPrice(6, priceDay6))));

        }

不多，但也许有人可以回答一些更聪明的方法。