Django 中 get_object_or_404 的问题

Question

我有一个错误，我似乎无法让我的代码的这部分工作。它给了我以下错误“element_id”是此函数的无效关键字参数。起初，我看到我没有调用正确的模型，我已经改变了它，但它似乎仍然不起作用。def Input(request, element_id, session_id):    input_element = get_object_or_404(InputData, pk=element_id)    voice_service = input_element.service    session = lookup_or_create_session(voice_service, session_id)    if request.method == "POST":        session = get_object_or_404(CallSession, pk=session_id)        value = 'DTMF input'        result = UserInput()        result.session = session        result.category = input_element.input_category         result.save()        return redirect(request.POST['redirect'])    session.input_step(input_element)    context = input_generate_context(input_element, session)    context['url'] = request.get_full_path(False)    return render(request, 'input.xml', context, content_type='text/xml')输入数据模型：class InputData(VoiceServiceElement):     """        An element that saves user input to a line in the database.    """    _urls_name = 'service-development:InputData'    ask_input_label = models.BooleanField(_('Ask the user to fill something in'), default=True)    input_voice_label = models.ForeignKey(        VoiceLabel,        verbose_name = _('Ask input label'),        help_text = _('The voice label that is played before the system asks the user to fill in the input'),        on_delete=models.SET_NULL,        null=True,        blank=True,        related_name='ask_input_label_input'    )    ask_confirmation = models.BooleanField(        _('Ask the caller to confirm their input'), default=True)    ask_confirmation_voice_label = models.ForeignKey(        VoiceLabel,        verbose_name = _('Ask for confirmation voice label'),        help_text = _('The voice label that asks the user to confirm their pinput. Example: "Are you satisfied with your recording? Press 1 to confirm, or press 2 to retry."'),        on_delete=models.SET_NULL,        null=True,        blank=True,        related_name='confirmation_voice_label_input',    )有人可以帮我吗？

Answer 1

您需要更新urls.py或更改您的views.py文件，以便 url 与函数名称匹配。

视图.py

def Input(request, element_id, session_id):

   ...

网址.py

app_name= 'service-development'

urlpatterns = [

    ...

    url(r'^InputData/(?P<element_id>[0-9]+)/(?P<session_id>[0-9]+)$', views.Input, name='Input')

]