如何在 PHP 中实现接受字符串参数并返回 JSON 格式的方法

Question

以下是定义水果颜色的数据结构示例：array(  "red" => array("apple, strawberry"),  "yellow" => array("lemon", "ripe mango"))实现函数 getFruits 方法，该方法接受颜色作为字符串参数并以 JSON 格式返回该颜色的所有水果（请参见下面的示例）。例如，调用 $fruitcolors->getFruits("red"); 应该返回：{“颜色”：“红色”，“水果”：[“苹果”，“草莓”]}如果调用没有该 $fruitcolors- getFruits("violet"); 的水果；颜色，它应该返回：{“颜色”：“紫罗兰”，“水果”：[] }<?phpclass FruitColor{  private $fruitcolor;  function FruitColor($fruitcolor)  {    $this->fruitcolor = $fruitcolor;  }  public function getFruits($color)  {    // @todo: implement here    return NULL;  }}$fruitcolor = new FruitColor(array(    "red" => array("apple", "strawberry"),    "yellow" => array("lemon", "ripe mango")));echo $fruitcolor->getFruits("red");echo "\n";echo $fruitcolor->getFruits("violet");

Answer 1

试试这个：

class FruitColor {

    private $fruitcolor;

    function __construct($fruitcolor)

    {

        $this->fruitcolor = $fruitcolor;

    }

    public function getFruits($color)

    {

        $fruits = array();

        if (isset($this->fruitcolor[$color])) {

            $fruits = $this->fruitcolor[$color];

        }

        return json_encode(array("color" => $color, "fruits" => $fruits));

    }

}

Answer 2

class FruitColor{

    private $fruitcolor;

    public function __construct( $fruitcolor ){

        $this->fruitcolor = $fruitcolor;

    }

    public function getFruits( $color ){

        if( array_key_exists( $color, $this->fruitcolor ) ){

            return json_encode( (object)array('color'=>$color, 'fruits' => $this->fruitcolor[ $color ]) );

        }

        return json_encode( (object)array('color'=>$color, 'fruits' => array() ) );

    }

}

$arr=array(

    "red"       => array("apple", "strawberry"),

    "yellow"    => array("lemon", "ripe mango")

);

$obj=new FruitColor( $arr );

$red=$obj->getFruits( 'red' );

$yellow=$obj->getFruits( 'yellow' );

$violet=$obj->getFruits( 'violet' );

printf('<pre>%s</pre>',print_r( $red,1));

printf('<pre>%s</pre>',print_r( $yellow,1));

printf('<pre>%s</pre>',print_r( $violet,1));

将输出：

{"color":"red","fruits":["apple","strawberry"]}

{"color":"yellow","fruits":["lemon","ripe mango"]}

{"color":"violet","fruits":[]}

Answer 3

这可能是您正在寻找的内容：

<?php

class FruitColor {

    private $data;

    function FruitColor($fruitcolors) {

        $this->data = $fruitcolors;

    }

    public function getFruits($color) {

        $fruits = [];

        if (isset($this->data[$color]) && is_array($this->data[$color])) {

            $fruits = $this->data[$color];

        }

        return json_encode(array("color" => $color, "fruits" => $fruits));

    }

}

$fruitcolor = new FruitColor([

    "red" => ["apple", "strawberry"],

    "yellow" => ["lemon", "ripe mango"]

]);

var_dump($fruitcolor->getFruits("red"));

var_dump($fruitcolor->getFruits("yellow"));

var_dump($fruitcolor->getFruits("violet"));

输出显然是：

string(47) "{"color":"red","fruits":["apple","strawberry"]}"

string(50) "{"color":"yellow","fruits":["lemon","ripe mango"]}"

string(30) "{"color":"violet","fruits":[]}"