如何打印解析为 php 对象的 json 字符串

Question

我有一个 JSON 字符串，我将其解析为 PHP 对象，我想从字符串中打印某些值，如何打印我需要的确切值。我提供了下面的代码{  "data":    {      "id":123,       "name": "abc",       "gsm":"1133",       "metadata":       {        "cart_id":13243      },       "customer":       {        "id":123,        "email": "[e-mail]"      }    }}json_decode($string);例如“名称”：abc，我只想打印 abc

Answer 1

您的 JSON 字符串无效，您在其中缺少括号。此外，字符串值必须在 json 中包含引号。你的字符串应该像

$string= '{

  "data": {

    "id": 123,

    "name": "abc",

    "gsm": 1133,

    "metadata": {

      "cart_id": 13243

    },

    "customer": {

      "id": 123,

      "email": "[e-mail]"

    }

  }

}';

$response = json_decode($string);

print_r($response->data->name);

die;

希望这对你有帮助。

Answer 2

您可以将 JSON 转换为数组并通过键访问元素

$jArr = json_decode($string, true);

访问元素

$jArr['data']['name']

Answer 3

您必须从 json 解码访问元素，如下所示：

$JSON = '{

    "data":{

        "id":123,

        "name": abc,

        "gsm":1133,

        "metadata":{

            "cart_id":13243

        },

        "customer":{

            "id":123,

            "email": "[e-mail]"

        }

    }

}'; //There were three errors, you have to to use ' insted of " for including the JSON string, you missed one '}' and you forgot the "" in the 'email' value under 'customer' section

$object = json_decode($JSON);

echo 'Printing the customer id using an object: '.$object->data->customer->id.PHP_EOL.PHP_EOL;

$array = json_decode($JSON, true);

echo 'Printing the customer id using an array: '.$array['data']['customer']['id'];

此代码打印：

Printing the customer id using an object: 123

Printing the customer id using an array: 123