如何将 Number.txt 文件转换为列表

Question

我想修复我曾经做过的代码中的逻辑和语法错误，但我重置了代码，认为它是错误的，从那以后一直无法弄清楚。我在代码中添加了 line = line.split，还将 numbers.append 更改为 numbers.sort，并将 int（我理解为什么 int 不起作用，但我不确定用什么替换它）来输入。主文件number_file=open("Numbers.txt")count=0numbers = []sum = 0for line in "Numbers.txt"数字.txt050100

Answer 1

我不是 100% 确定您要做什么，但这是基于我对您的问题的理解的答案：

# Create a list named numbers

numbers = []

# Open the input file in read only

with open ('Numbers.txt', 'r') as input:

  # read each line of the input file

  for line in input:

    # append each line to the list numbers

    # rstrip removes the \n from the strings

    numbers.append(line.rstrip())

print (type(numbers))

# outputs

<class 'list'>

print (numbers)

# outputs

['0', '50', '100']

# converts your list elements to int for summing 

results = list(map(int, numbers))

print (sum(results))

# outputs

150

如果这不正确，请告诉我，我会调整我的答案。

Answer 2

打开文件的一个好方法是使用上下文：

with open('path/to/file/Numbers.txt','r') as input_file:

    for line in input_file.readlines():

        do_stuff # knowing that they are string so you should convert to int