2 回答

TA贡献1828条经验 获得超13个赞
这是您想要的紧凑解决方案:
import csv
with open('sequences.txt', 'r') as f:
reader = csv.reader(f, delimiter=",")
for line in reader:
seq_lower = line[1].lower()
if 'aaaaaa' in seq_lower or 'cccccc' in seq_lower or 'tttttt' in seq_lower or 'gggggg' in seq_lower:
print(line)
在这里,我假设您在a,c,g,t处理 DNA 序列时只考虑 mnrs 。

TA贡献1786条经验 获得超13个赞
此后提出了使用正则表达式的部分解决方案。请注意,以下解决方案不适用于使用正则表达式,而是查找长度为 6 或更多的任何字符的任何序列。
测试数据:
number,sequence,status
1,kjhfklashfkldflkhasdfl,0
2,aaaaaljgkldfkjgldkfjgfldj,0
3,bbbbbbjigdfsjgjg,0
4,ccCccCCcjjfijsdfjsdf,0
5,klsjdflsjdfhdddddjnjlkhngjk,0
6,kjkljfhnlasjkdfheeeeeeejjjeeeeeeeeeekjdkljfleeef,0
7,jhfshffFffFFFFffkljjjj908u89,0
查找长度为 6 或更大的 MNR 的代码:
import csv
def contains_mnr(sequence):
start_char = "$" # choose a character that is sure not to be in the sequence
count = 0
seq_lower = sequence.lower()
for pos in range(0, len(seq_lower)):
if seq_lower[pos] == start_char:
count += 1
else:
start_char = seq_lower[pos]
count = 1
if count >= 6:
return True
return False
with open("input.csv", "r") as input_file:
with open("output.csv", "w") as output_file:
reader = csv.DictReader(input_file, dialect=csv.unix_dialect())
writer = csv.writer(output_file, dialect=csv.unix_dialect())
writer.writerow(reader.fieldnames)
for row in reader:
if contains_mnr(row["sequence"]):
writer.writerow([
row["number"],
row["sequence"],
row["status"]
])
请注意,可能需要根据运行代码和生成数据文件的系统调整 CSV 方言。
输出上面给出的测试数据:
"number","sequence","status"
"3","bbbbbbjigdfsjgjg","0"
"4","ccCccCCcjjfijsdfjsdf","0"
"6","kjkljfhnlasjkdfheeeeeeejjjeeeeeeeeeekjdkljfleeef","0"
"7","jhfshffFffFFFFffkljjjj908u89","0"
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