请问使用#include<iostream.h>//构造函数是进行初始化的，语法哪里有问题吗？

Question

#include<iostream.h>//构造函数是进行初始化的#include<math.h>class point{int x;int y;public:point(int m,int n)//构造函数{x=m;y=n;}int setx(){cout<<"please input x:";cin>>x;return x;}int sety(){cout<<"please input y:";cin>>y;return y;}void show(){cout<<"point("<<x<<","<<y<<")"<<endl;}friend int point::getTriange(point p1,point p2,point p3);};class Triangle{point p1;point p2;point p3;public:int getTriange(point p1,point p2,point p3){return (sqrt((p1.x-p2.x)*(p1.x-p2.x)+(p1.y-p2.y)*(p1.y-p2.y))+sqrt((p1.x-p3.x)*(p1.x-p3.x)+(p1.y-p3.y)*(p1.y-p3.y))+sqrt((p2.x-p3.x)*(p2.x-p3.x)+(p2.y-p3.y)*(p2.y-p3.y)));}void showc()//输出三个坐标{p1.show();p2.show();p3.show();}};void main(){point p1(1,1);point p2(2,2);point p3(3,3);//a.setx();//a.sety();p1.show();p2.show();p3.show();Triangle A;//定义一个三角形变量AA.getTriange();A.showc();}哪里出现错误了

Answer 1

不知你想要验证什么，给你改得能运行了：
#include<iostream.h>//构造函数是进行初始化的
#include<math.h>

class point{
int x;
int y;
public:
point(int m=0,int n=0)//构造函数
{
x=m; y=n;
}
void setx()
{
cout<<"please input x:";
cin>>x;
// return x;
}
void sety()
{
cout<<"please input y:";
cin>>y;
// return y;
}
void show()
{
cout<<"point("<<x<<","<<y<<")"<<endl;
}
friend class Triangle;
};

class Triangle{
point p1;
point p2;
point p3;
public:
double getTriange()
{
return (sqrt((p1.x-p2.x)*(p1.x-p2.x)+(p1.y-p2.y)*(p1.y-p2.y))+sqrt((p1.x-p3.x)*(p1.x-p3.x)+(p1.y-p3.y)*(p1.y-p3.y))+sqrt((p2.x-p3.x)*(p2.x-p3.x)+(p2.y-p3.y)*(p2.y-p3.y)));
}
void showc()//输出三个坐标
{
p1.show();
p2.show();
p3.show();
}
};

void main()
{
point p1(1,1);
point p2(2,2);
point p3(3,3);
//a.setx();
//a.sety();
p1.show();
p2.show();
p3.show();
Triangle A;//定义一个三角形变量A
A.getTriange();
A.showc();
}