下面我们有 2 个 int 数组，用于存储主客场的足球比赛结果……我需要显示我有多少平局结果的统计数据。有人可以帮我看看吗？我想不通。请假设这是我的第一次曾经编程，如果你有任何解决方案，你可以评论代码吗..我需要向我的导师解释我是如何做到的。谢谢 String[] HomeTeam = new String[10]; String[] AwayTeam = new String[10]; int[] HomeScore = new int[10]; int[] AwayScore = new int[10]; int index = 0; int sum = 0; int sum1 = 0; do { System.out.print("Enter Home Team Name: "); HomeTeam[index] = kbd.nextLine(); System.out.print("Enter Away Team Name: "); AwayTeam[index] = kbd.nextLine(); System.out.print("Enter Home Team Score:"); HomeScore[index] = kbd.nextInt(); System.out.print("Enter Away Team Score: "); AwayScore[index] = kbd.nextInt(); kbd.nextLine(); } while(index < 10); index = 0; System.out.println(); do { System.out.println(HomeTeam[index] + " [" + HomeScore[index] + "]" + " | " + AwayTeam[index] + " [" + AwayScore[index] + "] "); index = index + 1; } while(index < 10); kbd.close(); for(index = 0; index < 10; index++) sum += HomeScore[index]; for(index = 0; index < 10; index++) sum1 += AwayScore[index]; System.out.println(); System.out.println("Totals"); System.out.println("-------------------------------"); System.out.println("Total number of matches played: " + index); System.out.println("Total of all home scores: " + sum); System.out.println("Total of all away scores: " + sum1); System.out.println("Total number of draws: "); System.out.println("The highest home score: "); System.out.println("The highest away score: ");}}
3 回答
HUH函数
TA贡献1836条经验 获得超4个赞
为了编写您的代码，您必须清楚您正在实施的解决方案。一个很好的初学者练习，是写一个程序执行的流程图（键盘前的纸）。
我做了一个供你将来参考：
因此，考虑到该算法，我实现了一个可能的解决方案（使用硬编码数据）。
主类：
public class MainE {
public static void main(String[] args) {
String[] homeTeam = { "q", "w", "e", "r", "t", "y", "u", "i", "o", "p"};
String[] awayTeam = {"p", "o", "i", "u", "y", "t", "r", "e", "w", "q"};
int[] homeScore = {5,1,3,5,6,1,10,4,3,2};
int[] awayScore = {4,3,2,1,3,5,42,1,3,2};
int sumHome = 0;
int sumAway = 0;
int drawCount = 0;
int highestHomeScore = homeScore[0];
int highestAwayScore = awayScore[0];
System.out.println();
for (int index = 0; index < 10; index++) {
System.out.println(homeTeam[index] + " [" + homeScore[index] + "]"
+ " | " + awayTeam[index] + " [" + awayScore[index] + "] ");
sumHome += homeScore[index];
sumAway += awayScore[index];
if (homeScore[index] > highestHomeScore) highestHomeScore = homeScore[index];
if (awayScore[index] > highestAwayScore) highestAwayScore = awayScore[index];
if(homeScore[index] == awayScore[index]) drawCount++;
}
System.out.println();
System.out.println("Totals");
System.out.println("-------------------------------");
System.out.println("Total number of matches played: " + homeTeam.length);
System.out.println("Total of all home scores: " + sumHome);
System.out.println("Total of all away scores: " + sumAway);
System.out.println("Total number of draws: " + drawCount);
System.out.println("The highest home score: " + highestHomeScore);
System.out.println("The highest away score: " + highestAwayScore);
}
}
输出：
q [5] | p [4]
w [1] | o [3]
e [3] | i [2]
r [5] | u [1]
t [6] | y [3]
y [1] | t [5]
u [10] | r [42]
i [4] | e [1]
o [3] | w [3]
p [2] | q [2]
Totals
-------------------------------
Total number of matches played: 10
Total of all home scores: 40
Total of all away scores: 66
Total number of draws: 2
The highest home score: 10
The highest away score: 42
编辑：
如果你想避免空值，你必须询问每次迭代if(homeTeam[index] != null )，也手动计算匹配（它们不再匹配数组长度）
句柄空
public class MainE {
public static void main(String[] args) {
String[] homeTeam = { "q", "w", "e", null, "t", "y", "u", "i", "o", "p"};
String[] awayTeam = {"p", "o", "i", null, "y", "t", "r", "e", "w", "q"};
int[] homeScore = {5,1,3,0,6,1,10,4,3,2};
int[] awayScore = {4,3,2,0,3,5,42,1,3,2};
int sumHome = 0;
int sumAway = 0;
int drawCount = 0;
int matches = 0;
int highestHomeScore = homeScore[0];
int highestAwayScore = awayScore[0];
System.out.println();
for (int index = 0; index < 10; index++) {
if(homeTeam[index] != null ){
System.out.println(homeTeam[index] + " [" + homeScore[index] + "]"
+ " | " + awayTeam[index] + " [" + awayScore[index] + "] ");
sumHome += homeScore[index];
sumAway += awayScore[index];
if (homeScore[index] > highestHomeScore) highestHomeScore = homeScore[index];
if (awayScore[index] > highestAwayScore) highestAwayScore = awayScore[index];
if(homeScore[index] == awayScore[index]) drawCount++;
matches++;
}
}
System.out.println();
System.out.println("Totals");
System.out.println("-------------------------------");
System.out.println("Total number of matches played: " + matches);
System.out.println("Total of all home scores: " + sumHome);
System.out.println("Total of all away scores: " + sumAway);
System.out.println("Total number of draws: " + drawCount);
System.out.println("The highest home score: " + highestHomeScore);
System.out.println("The highest away score: " + highestAwayScore);
}
}
输出：
q [5] | p [4]
w [1] | o [3]
e [3] | i [2]
t [6] | y [3]
y [1] | t [5]
u [10] | r [42]
i [4] | e [1]
o [3] | w [3]
p [2] | q [2]
Totals
-------------------------------
Total number of matches played: 9
Total of all home scores: 35
Total of all away scores: 65
Total number of draws: 2
The highest home score: 10
The highest away score: 42
注意：更好的选择是在询问输入时跳过空值。
喵喔喔
TA贡献1735条经验 获得超5个赞
您的代码中有 2 个 for 循环，但您只需要 1 个即可获得所需的所有结果，因为所有数组的大小均为 10。
因此在此循环中：
for(index = 0; index < 10; index++) {
// calculations
}
通过index在所有数组中使用，计算主队和客队的所有总和、平局数和最高分。
还有一个建议：为变量使用更易读的名称，例如：
sumMatches, sumHomeScore, sumAwayScore, sumDraws, sumHighestHome, sumHighestAway。
海绵宝宝撒
TA贡献1809条经验 获得超8个赞
添加另一个名为drawCount. 循环遍历 score 数组并检查循环索引处两个数组中的元素是否相等。如果是，则加drawCount一。然后在最后打印。
此外，您可以将For循环合二为一。
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