将文本文件读取为 dict

Question

我的文本文件看起来像这样..每行由一个空格分隔。dream 4.345 0.456 6.3456play 0.1223 -0.345 5.3543faster 1.324 2.435 -2.2345我想写字典并将其打印如下...dream: [4.345 0.456 6.3456]play: [0.1223 -0.345 5.3543]faster: [1.324 2.435 -2.2345]我的代码如下。请纠正我这个...with open("text.txt", "r") as file:     for lines in file:        line = lines.split()        keys = b[0]         values = b[1:]        d[keys] = valuesprint d

Answer 1

对于 python3，如果你想得到想要的结果：

d = {}

with open("text.txt", "r") as file:

    for lines in file:

    line = lines.split()

    keys = line[0] 

    values = list(map(float, line[1:]))

    d[keys] = values

for k in d :

    print(k , d[k])

Answer 2

你可以这样试试。

输入.txt

dream 4.345 0.456 6.3456

play 0.1223 -0.345 5.3543

faster 1.324 2.435 -2.2345

编写器.py

output_text = '' # Text

d = {} # Dictionary

with open("input.txt") as f:

    lines = f.readlines()

    for line in lines:

        line = line.strip()

        arr = line.split()

        name = arr[0]

        arr = arr[1:]

        d[name] = arr

        output_text += name + ": [" + ' '.join(arr) + "]\n"

output_text = output_text.strip() # To remove extra new line appended at the end of last line

print(d)

# {'play': ['0.1223', '-0.345', '5.3543'], 'dream': ['4.345', '0.456', '6.3456'], 'faster': ['1.324', '2.435', '-2.2345']}

print(output_text)

# dream: [4.345 0.456 6.3456]

# play: [0.1223 -0.345 5.3543]

# faster: [1.324 2.435 -2.2345]

with open("output.txt", "w") as f:

    f.write(output_text)

输出.txt

dream: [4.345 0.456 6.3456]

play: [0.1223 -0.345 5.3543]

faster: [1.324 2.435 -2.2345]

Answer 3

这很简单。请参阅下面的代码。

  dictionary = {}

  with open("text.txt", "r") as file:  

      for lines in file:

          line = lines.split()

          dictionary[line[0]] = line[1:]

  print(dictionary)