在python中比较1d和2d系列的有效方法

Question

你想找到奇数 inedx ，但你真正要做的是找到奇数元素for i in lst:  #(i ---->the element in lst)       if i % 2 == 1:所以你应该试试这个for i in range(len(lst)): #( i ---> the index of lst)    if i % 2 == 1:

Answer 1

pandas.Series实现了combine方法，您可以通过以下方式使用该方法来查找b也出现在a列表中的元素：

import pandas as pd

a = pd.Series([["a","b","c", "d"],["a","b","c", "d"],["a","b","c", "d"],["a","b","c", "d"],["a","b","c", "d"]])

b = pd.Series(["a","d","e", "c", "b"])

a.combine(b, lambda a,b: b in a)

输出：

0     True

1     True

2    False

3     True

4     True

dtype: object

Answer 2

这应该适合你：

import pandas as pd

a = pd.Series([["a","b","c", "d"],["a","b","c", "d"],["a","b","c", "d"],["a","b","c", "d"],["a","b","c", "d"]])

b = pd.Series(["a","d","e", "c", "b"])

[x in y for y,x in zip(a,b)]

...输出为：

[True, True, False, True, True]