3 回答
![?](http://img1.sycdn.imooc.com/54584d080001566902200220-100-100.jpg)
TA贡献1810条经验 获得超5个赞
您可以使用以下方法来实现这一点:-
data = None
with open('file.txt', 'r') as file:
data = file.read()
def process_line_item(x):
index = x[0]
line_str = x[1]
new_first_value = [str(x[0])] # you can put here new value depending on line index
return ' '.join(new_first_value + x[1].split(' ')[1:])
new_data = '\n'.join(list(map(process_line_item, enumerate(data.split('\n')))))
with open('new_file.txt', 'w') as file:
file.write(new_data)
file.txt
12.32 1:34 2:49 5:21 29:98
13.53 1:23 2:82 5:23 29:45
51.92 1:23 2:54 5:54 29:63
12.42 1:34 2:43 5:32 29:32
new_file.txt
0 1:34 2:49 5:21 29:98
1 1:23 2:82 5:23 29:45
2 1:23 2:54 5:54 29:63
3 1:34 2:43 5:32 29:32
![?](http://img1.sycdn.imooc.com/54586431000103bb02200220-100-100.jpg)
TA贡献1830条经验 获得超3个赞
您可以使用该csv模块delimiter=" ":
from csv import reader
with open('file.txt', 'r') as file:
csv_reader = reader(file, delimiter=" ")
for row in csv_reader:
row[0] = '??.??'
print(row)
哪个输出
['??.??', '1:34', '2:49', '5:21', '29:98']
['??.??', '1:23', '2:82', '5:23', '29:45']
...
请注意,您的数字将是字符串。您可能需要将它们转换为浮点数:
floats = [float(item) for item in row]
如果您需要将更改写入文件,您可以类似地使用csv.writer.
![?](http://img1.sycdn.imooc.com/5333a207000118af02200220-100-100.jpg)
TA贡献2021条经验 获得超8个赞
这段代码应该可以解决问题,但是它可能有点错误,可能需要稍微调整和测试。我希望它有帮助。
with open('file.txt', 'r') as file:
file_content = file.read()
list_content = [letter for letter in file_content]
num_length = 0
for i, char in enumerate(list_content):
num_length += 1
if list_content[i - 1] == '\n':
num_length = 0
elif char == ' ':
start_index = i - num_length
for _ in range(num_length + 1):
list_content.pop(start_index)
list_content.insert(start_index, your_new_number)
out_text = ''.join(list_content)
with open('file.txt', 'w+') as file:
file.write(out_text)
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