如何以json格式编写特定的C#属性值？

Question

我有一些属性，我想以 json 格式保存一些特定的属性值。这是我的代码，我想保存两个属性值，如 SelectedScalesModel 和 SelectedScales port 谁能帮我解决这个问题。public class SetUpViewModel : ViewModelBase{    public List<string> ScalesModel { get; set; } = new List<string> { "None", "METTLER-TOLEDO", "DINI ARGEO DFW-DFWK", "ESSAE SI-810" };    private string _selectedScalesModel;    public string SelectedScalesModel    {        get { return _selectedScalesModel; }        set        {            _selectedScalesModel = value;            RaisePropertyChanged("SelectedScalesModel");        }    }    public List<string> ScalesPort { get; set; } = new List<string> { "None", "COM1", "COM2", "COM3", "COM4", "COM5", "COM6", "COM7", "COM8", "COM9", "COM10", "COM11", "COM12", "COM13", "COM14", "COM15" };    private string _selectedScalesPort;    public string SelectedScalesPort    {        get { return _selectedScalesPort; }        set        {            _selectedScalesPort = value;            RaisePropertyChanged("SelectedScalesPort");        }    }    string _text1;    public string BlackLineText    {        get { return _text1; }        set        {            _text1 = value;            RaisePropertyChanged(nameof(BlackLineText));        }    }    public RelayCommand SaveButtonCommand { get; private set; }    public SetUpViewModel()    {        SaveButtonCommand = new RelayCommand(SaveCommand);    }    private void SaveCommand()    {        SetUpViewModel setUpobj = new SetUpViewModel();        string strJsonResult = JsonConvert.SerializeObject(setUpobj);        File.WriteAllText("setup.json", strJsonResult);        MessageBox.Show("File save in Json Format");    }}

Answer 1

您可以尝试SerializeObject通过匿名类然后携带您的期望属性而不是SetUpViewModel对象。

private void SaveCommand()

{

    string strJsonResult = JsonConvert.SerializeObject(

        new {

            SelectedScalesModel = this.SelectedScalesModel,

            SelectedScalesPort = this.SelectedScalesPort

        }

    );

    File.WriteAllText("setup.json", strJsonResult);

    MessageBox.Show("File save in Json Format");

}

笔记

使用this因为您的对象中的属性信息。