3 回答
![?](http://img1.sycdn.imooc.com/5333a0350001692e02200220-100-100.jpg)
TA贡献2012条经验 获得超12个赞
因此,将第一个参数定义为另一个变量,并对其余值使用价差。
function averageString(str, ...numbers) {
let sum = 0;
numbers.forEach(function (x) {
sum += x;
});
return `The average of ${str} is ${sum / numbers.length}`
}
console.log(averageString('age', 12, 15, 20))
console.log(averageString('foo', 1, 1, 1, 1, 1, 1, 1))
![?](http://img1.sycdn.imooc.com/54584f6d0001759002200220-100-100.jpg)
TA贡献1815条经验 获得超13个赞
我真的不明白传递字符串的目的是什么,但是您可以在数组中传递数字并且您的函数应该可以工作。
function averageString(myStr, numbers) {
let sum = 0;
numbers.forEach(function (x) {
sum += x;
});
return 'The average of ' + myStr + ' is ' + (sum / numbers.length);
}
console.log(averageString('age', [12, 15, 20]));
![?](http://img1.sycdn.imooc.com/545865470001bf9402200220-100-100.jpg)
TA贡献1871条经验 获得超8个赞
您想为数字变量使用数组。
function averageString(name,numbers) {
let sum = 0;
numbers.forEach(function (x) {
sum += x;
});
return 'The average of (' + name + ') is ' + sum / numbers.length;
}
document.getElementById("returnVal").innerHTML = averageString('age',[12, 15, 20])
https://jsfiddle.net/31j5p7zf/
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