使用 JavaScript 检查输入数字是否在范围内

Question

检查输入是否在数组范围内。假设，如果输入值为 12，答案应该是球。var ranges = [{"1-10":"Apple"},{"11-20":"Ball"},{"21-30":"Cat"}]var input_number = 12;var get_answer = ...  // should be "Ball"

Answer 1

简单的代码给你

var ranges = [{"1-10":"Apple"},{"11-20":"Ball"},{"21-30":"Cat"}]

function getAns(input_number) {

  let result = null

  // handle input ranges

  for (let index in ranges) {

    for (let key in ranges[index]) {

      let min = key.split('-')[0]

      let max = key.split('-')[1]

      if (input_number >= min && input_number <= max) {

        result = ranges[index][key]

      }

    }

  }

  return result

}

console.log(getAns(12))

Answer 2

我会使用过滤器

const getValue = (value, ranges) => {

  const res = ranges.filter(obj => {

    const [min, max] = Object.keys(obj)[0].split("-");

    return value >= +min && value <= +max;

  })

  return res && res.length > 0 ?  Object.values(res[0])[0] :  "N/A"

}

const ranges = [{"1-10":"Apple"},{"11-20":"Ball"},{"21-30":"Cat"}]

console.log(getValue(0,ranges))

console.log(getValue(1,ranges))

console.log(getValue(12,ranges))

console.log(getValue(30,ranges))

console.log(getValue(31,ranges))

Answer 3

尝试

ranges.map(x=> Object.entries(x).flat() )
       .find(a=> (a[0]=a[0].split`-`, n>=a[0][0] && n<=a[0][1] && a[1]) )

var ranges = [{"1-10":"Apple"},{"11-20":"Ball"},{"21-30":"Cat"}]

var n=12;

var r = ranges.map( x=>Object.entries(x).flat() )

              .find(a=> (a[0]=a[0].split`-`, n>=a[0][0] && n<=a[0][1] && a[1]) )

console.log(r[1]);