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TA贡献1825条经验 获得超4个赞
一种方法是将包含列表的单元格分解为单独的行,然后应用 LabelEncoder,然后将这些行组合回列表:
df_encoded = pd.DataFrame()
df_decoded = pd.DataFrame()
def t1(z):
zz = pd.DataFrame([np.array(x).reshape(-1) for x in z.values.tolist()])
dt = zz.dtypes[0]
return (zz
.stack()
.reset_index(level=1, drop=True)
.to_frame(col)
.astype(dt))
def t2(z):
return z.groupby(level=0).apply(lambda x: np.squeeze(x.values.tolist()))
for col in dj.columns:
d = t1(dj[col])
d['x'] = le.fit_transform(d[col])
df_encoded[col] = t2(d['x'])
print(df_encoded)
for col in dj.columns:
d = t1(dj[col])
m = le.fit(d[col])
d = t1(df_encoded[col])
d['x'] = m.inverse_transform(d[col])
df_decoded[col] = t2(d['x'])
print(df_decoded)
输出:
A B
0 [0, 1] 1
1 0 [1, 2]
2 1 0
3 2 1
A B
0 [1, 2] p
1 1 [p, q]
2 2 o
3 3 p
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