3 回答
TA贡献1836条经验 获得超4个赞
将 JSON解组到 []interface{}并将结果插入到数据库中。假设它c是一个mgo.Collection并且data是一个包含 JSON 值的 []byte,请使用以下代码:
var v []interface{}
if err := json.Unmarshal(data, &v); err != nil {
// handle error
}
if err := c.Insert(v...); err != nil {
// handle error
}
TA贡献1875条经验 获得超3个赞
在这个例子中,我将存储混合数组
测试字符串:= '[[1,"a","b",2,"000000",[[1,2,3],[1,2,3]],"\"x","[y","'z",[[1,2,3],[1,2,3]]]]'
在 mongodb 中作为 json:
{datum: [[1,"a","b",2,"000000",[[1,2,3],[1,2,3]],"\"x","[y","'z",[[1,2,3],[1,2,3]]]]}
package main
import (
"strings"
"context"
"encoding/json"
"fmt"
"log"
"net/http"
"go.mongodb.org/mongo-driver/bson"
"go.mongodb.org/mongo-driver/bson/primitive"
)
type datum2 struct {
Datum interface{} `json:datum`
}
var userCollection = db().Database("goTest").Collection("users") // get collection "users" from db() which returns *mongo.Client
func typeinterface2mongo() {
var datum2 datum2_instance
var interfacevalue []interface{}
test_string := `[[1,"a","b",2,"000000",[[1,2,3],[1,2,3]],"\"x","[y","'z",[[1,2,3],[1,2,3]]]]`
if err := json.Unmarshal([]byte(test_string), &interfacevalue); err != nil {
fmt.Println(err)
return
}
fmt.Println(test_string)
fmt.Println(interfacevalue)
datum2_instance.Datum=interfacevalue
userCollection.InsertOne(context.TODO(), datum2_instance)
fmt.Println(datum2_instance)
fmt.Println(datum2_instance.Datum)
}
TA贡献1841条经验 获得超3个赞
如果您已经有 json 数据,请从第 2 步开始操作。
如果您先有 Xml 数据,则需要使用此包(“github.com/basgys/goxml2json”)转换为 json 格式
type JsonFileResponse struct {
JsonData string `bson:"JsonData " json:"JsonData"`
}
step 1: jsonData, err := xml2json.Convert(xml)
if err != nil {
panic("getting error while converting xml to json",err)
}
step 2: session need to open by using your mongodb credentials.
collection := session.DB("database name").C("Collection Name")
err = collection.Insert(JsonFileResponse{JsonData :json.String()})
if err != nil {
log.Fatal(err)
}
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