我正在使用 bootstrap-table 库在我的 ASP.net MVC 视图中创建一个表。每当用户双击表格行时，要求是选择表格行数据并将其传输到模型弹出窗口。我可以在 Javascript 中使用 row[] 数组选择行列值，但我无法通过 Ajax 将其传输到我的控制器。请在我的代码片段下方找到：-<html><head><script>$(document).ready(function () {$('#tblID').bootstrapTable({ locale: 'en-US' }).on('click-row.bs.table', function (e, row, $element) {var param = row[2]; //fetching 3rd column value$.ajax({ type: "GET", url: '@Url.Action("_SampleAction", "SampleController")', data: '{ID: "' + param + '" }', datatype: "json", success: function (result) { $('#myModelContent').html(result); $("#myModal").modal('show'); }, error: function (req, status, error) { alert("Error!Occured"); } });});});</script></head><body><table id="tblID" class="table table-hover" data-search="true" data-show-columns="true" data-mobile-responsive="true" data-striped="true" data-toggle="table" data-sort-name="Salary" data-sort-order="desc" data-pagination="true" data-smart-display="true" data-filter-control="true" data-show-export="true" data-click-to-select="true" data-page-list="[5, 10, 25, 50, 100, ALL]" data-export-options='{"fileName": "ActiveList","ignoreColumn": ["state"]}'> <thead> <tr> @foreach (DataColumn col in Model.Details.Columns) { <th class="TableRowHeader" data-sortable="true" data-filter-control="Select">@col.ColumnName</th> } </tr> </thead>样本控制器：-public ActionResult _SampleAction(string ID) { MyModel objMyModel = new MyModel (); objMyModel.ID = ID; try { return PartialView("_SampleAction", objMyModel); } catch (Exception ex) { return RedirectToAction("Index", "Error"); } }但是我收到的参数ID为 null，Ajax 调用失败。谁能指导我如何实现这一目标？
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30秒到达战场
TA贡献1828条经验 获得超6个赞
AJAX 回调不打算执行重定向到另一个操作方法（也data使用字符串连接分配参数data: '{ID: "' + param + '" }'肯定是错误的）。尝试配置 AJAX 回调以查看错误消息是否存在，如下所示：
$.ajax({
type: "GET",
url: '@Url.Action("_SampleAction", "SampleController")',
data: { ID: param }, // proper way to pass string to controller with AJAX
// other AJAX settings
success: function (result) {
if (result.message == undefined) {
$('#myModelContent').html(result);
$("#myModal").modal('show');
} else {
// set redirection here instead of using RedirectToAction from controller
window.location.href = result.url;
}
},
error: function (req, status, error) {
alert("Error occurred");
}
});
});
并且控制器动作应该在异常发生时返回 JSON 数据，如下所示：
public ActionResult _SampleAction(string ID)
{
MyModel objMyModel = new MyModel();
objMyModel.ID = ID;
try
{
// do something
return PartialView("_SampleAction", objMyModel);
}
catch (Exception ex)
{
return Json(new { url = Url.Action("Index", "Error"), message = ex.Message }, JsonRequestBehavior.AllowGet);
}
}
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