过滤对象中的多个值

Question

我需要通过多个值过滤一个对象。对象示例：items: [{url: "https://...",id: "1693",type: "ABC",currencyCode: "SEK",longName: "Abc",name: "ABC",micCode: "DEF",listingDate: "2018-05-25T00:00:00+02:00",subType: "STOCK",  market: {   id: "NOROTC"},}.....如果我过滤一个值就可以了：var market = data.filter(item => item.market.id === 'NOROTC');但我需要做的是：var market = data.filter(item => item.market.id === 'NOROTC' && item.market.id === 'NGM');我在 stackoverflow 上发现了一些类似的帖子，但在我的情况下，它们似乎都不起作用。有没有聪明的方法来做到这一点？我也试过 _.filter() 但没有成功......

Answer 1

请检查以下示例：

var items = [{

    name: 'Amit',

    id: 101

  },

  {

    name: 'Amit',

    id: 1011

  },

  {

    name: 'Arthit',

    id: 102

  },

  {

    name: 'Misty',

    id: 103

  },

]

var filteredData = items.filter(item => item.name == 'Amit' || item.name== 'Misty');

console.log(filteredData)

Answer 2

您可以拥有要过滤的 ID 数组并用于Array.includes()过滤数组，如下所示：

var items = [

  {market: {id: "NOROTC"}},

  {market: {id: "NGM"}},

  {market: {id: "foo"}},

  {market: {id: "bar"}},

]

var searchItems = ["NOROTC","NGM"]

var filteredData = items.filter(item => searchItems.includes(item.market.id))

console.log(filteredData)