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循环运行python脚本并将输出打印到文件

循环运行python脚本并将输出打印到文件

白衣非少年 2021-11-23 20:07:01
我有以下 python 脚本:import somethingresponse = requests.get('https://example.com/folder/1')data = stuff_hereprint(data)我想为 URL 值 1 到 100 运行此脚本并将输出保存到1.txt, 2.txt ... 100.txt。任何想法我怎么能做到这一点?
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2 回答

?
慕的地8271018

TA贡献1796条经验 获得超4个赞

这应该可以解决问题:


# Firstly you import what you need to import

import something


# For-loop which runs from values 1 to 101 (101 is non-inclusive)

# with each value being stored in to 'i'

for i in range(1, 101):

    # Runs requests.get() method on the URL

    # URL is made by f-formatting a string ('{i}' will get replaced with the value of 'i')

    response = requests.get(f'https://example.com/folder/{i}')


    # Does 'stuff_here' and stores it in 'data'

    data = stuff_here


    # Prints out data

    print(data)


    # with keyword opens the file f'{i}.txt' in "w" mode,

    #  and stores is in to the 'file' variable.

    # f'{i}.txt' is, again, an f-formatted string which replaces '{i}' with the value of i

    # "w" mode is writing mode, you can write to a file while using it

    with open(f"{i}.txt", "w") as file:

        # Writes the contents of 'data' to the file 'file'

        file.write(data)


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反对 回复 2021-11-23
?
偶然的你

TA贡献1841条经验 获得超3个赞

像这样的东西:


import requests



input_list = []


for i in range(1, 101):

    input_list.append(('https://example.com/folder/{}'.format(i), "{}.txt".format(i)))



for input_ in input_list:

    req = requests.get(input_[0])

    if (req.status_code == 200):

        result = req.text

    else:

        result = "Failed Request {}".format(req.status_code)

    with open(input_[1], "w") as f:

        f.write(result)


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反对 回复 2021-11-23
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