PHP JSON Array - 如何按相同的值修改 json 代码组

Question

我使用 php foreach 函数按具有相同值的对象对我的表进行分组$data = json_decode($geo, true);$out = [];foreach($data as &$element) {     $out[$element['id']][] = [        'lng' => $element['lng'],        'lat' => $element['lat'],        'time' => $element['time']    ];};$geo = json_encode($out);后来我得到了这个结果"[{"1":[{"lng":134.94157,"lat":36.871337,"time":1502159287}],"2":[{"lng":134.94157,"lat":34.598832,"time":1502211838}],"3":[{"lng":131.225,"lat":37.101667,"time":1502144333},{"lng":131.24,"lat":37.123333,"time":1502144343}]}]"现在我希望我的数据是这样的[[{"lng":134.94157,"lat":36.871337,"time":1502159287}],[{"lng":134.94157,"lat":34.598832,"time":1502211838}],[{"lng":131.225,"lat":37.101667,"time":1502144333},{"lng":131.24,"lat":37.123333,"time":1502144343}]]我怎样才能做到这一点？

Answer 1

首先，json_decode()您的初始 JSON 数据。然后，移动到解码数据中的第一个索引，并在array_values()的帮助下仅选择跳过键的数组值的值。

<?php

$prev_json = '[{"1":[{"lng":134.94157,"lat":36.871337,"time":1502159287}],"2":[{"lng":134.94157,"lat":34.598832,"time":1502211838}],"3":[{"lng":131.225,"lat":37.101667,"time":1502144333},{"lng":131.24,"lat":37.123333,"time":1502144343}]}]';

$data = json_decode($prev_json,true);

$new_json = json_encode(array_values($data[0]));

echo $new_json;

演示： https : //3v4l.org/bFmYn

更新：查看更新后的代码，您可以删除$element['id']from$out[$element['id']]并使其$out[] = [..rest of your code..]正常工作。