如何遍历列表的列？

Question

我正在尝试遍历列表列表。我想找到列表中列的最小值和最大值。这是清单：['Afghanistan', 2.66171813, 7.460143566, 0.490880072, 52.33952713, 0.427010864, -0.106340349, 0.261178523]['Albania', 4.639548302, 9.373718262, 0.637698293, 69.05165863, 0.74961102, -0.035140377, 0.457737535]['Algeria', 5.248912334, 9.540244102, 0.806753874, 65.69918823, 0.436670482, -0.194670126, 0]['Argentina', 6.039330006, 9.843519211, 0.906699121, 67.53870392, 0.831966162, -0.186299905, 0.305430293]['Armenia', 4.287736416, 9.034710884, 0.697924912, 65.12568665, 0.613697052, -0.132166177, 0.246900991]['Australia', 7.25703764, 10.71182728, 0.949957848, 72.78334045, 0.910550177, 0.301693261, 0.45340696]我试图遍历从li[1]到 的每一列li[-1]。我试过了：j = 1small = []while j < len(li)    for i in range(0, len(newlist)):        small.append(newlist[i][j])    print(max(small))    print(min(small))    j = j + 1输出：7.257037642.66171813我得到了第一列，但我正在努力遍历下一列。

Answer 1

您可以使用zip. 鉴于您的数据集为my_list：

my_lists = [['Afghanistan', 2.66171813, 7.460143566, 0.490880072, 52.33952713, 0.427010864, -0.106340349, 0.261178523],

['Albania', 4.639548302, 9.373718262, 0.637698293, 69.05165863, 0.74961102, -0.035140377, 0.457737535],

['Algeria', 5.248912334, 9.540244102, 0.806753874, 65.69918823, 0.436670482, -0.194670126, 0],

['Argentina', 6.039330006, 9.843519211, 0.906699121, 67.53870392, 0.831966162, -0.186299905, 0.305430293],

['Armenia', 4.287736416, 9.034710884, 0.697924912, 65.12568665, 0.613697052, -0.132166177, 0.246900991],

['Australia', 7.25703764, 10.71182728, 0.949957848, 72.78334045, 0.910550177, 0.301693261, 0.45340696]]

for t in list(zip(*my_lists))[1:]:

    print(max(t), min(t))

7.25703764 2.66171813

10.71182728 7.460143566

0.949957848 0.490880072

72.78334045 52.33952713

0.910550177 0.427010864

0.301693261 -0.194670126

0.457737535 0

Answer 2

下面的代码使用列表理解创建了一个包含每个列表最小值和最大值的元组列表，您可以进一步格式化以在每个元组中包含国家/地区名称。

li = [['Afghanistan', 2.66171813, 7.460143566, 0.490880072, 52.33952713, 0.427010864, -0.106340349, 0.261178523],

    ['Albania', 4.639548302, 9.373718262, 0.637698293, 69.05165863, 0.74961102, -0.035140377, 0.457737535],

    ['Algeria', 5.248912334, 9.540244102, 0.806753874, 65.69918823, 0.436670482, -0.194670126, 0],

    ['Argentina', 6.039330006, 9.843519211, 0.906699121, 67.53870392, 0.831966162, -0.186299905, 0.305430293],

    ['Armenia', 4.287736416, 9.034710884, 0.697924912, 65.12568665, 0.613697052, -0.132166177, 0.246900991],

    ['Australia', 7.25703764, 10.71182728, 0.949957848, 72.78334045, 0.910550177, 0.301693261, 0.45340696]]

li2 = [(min(y),max(y)) for y in [[x for x in l[1:]] for l in li]]

print (li2)

Answer 3

columns=len(newlist[0])

rows=len(newlist)

for i in range(1,columns):

    for j in range(rows):

        small.append(newlist[j][i])

    print("{}. columuns min value:{} max value:{}".format(i,min(small),max(small)))