2 回答
TA贡献1906条经验 获得超10个赞
我得到了一个使用 Zip 存档的解决方案,我创建了一个静态类来将内存流推送到一个 zip 存档中,如下所示,
var pushStreamContent = ZipStreamContent.Create("MultipleDocument.zip", memStList);
ZipStreamContent 类,
public static class ZipStreamContent
{
public static PushStreamContent Create(string fileName, List<MemoryStream> msList)
{
var content = new PushStreamContent((outputStream, httpContent, transportContext) =>
{
using (var zip = new ZipArchive(outputStream, ZipArchiveMode.Create, leaveOpen: false))
{
msList[0].Position = 0;
var createenter = zip.CreateEntry("xyz.jpg", CompressionLevel.Optimal);
using (var s = createenter.Open())
{
msList[0].CopyTo(s);
}
}
});
content.Headers.ContentType = new MediaTypeHeaderValue("application/octet-stream");
content.Headers.ContentDisposition = new ContentDispositionHeaderValue("attachment");
content.Headers.ContentDisposition.FileName = fileName;
return content;
}
}
TA贡献1785条经验 获得超4个赞
我已经简化了上面给出的 GipStreamContent 静态类,如下所示,它运行良好,所以我希望它能帮助所有其他人。
CloudBlockBlob blob = null;
//azure storage connection
var container = GetBlobClient(tenantInfo);
//directory reference
var directory = container.GetDirectoryReference(
string.Format(DirectoryNameConfigValue, tenantInfo.TenantId.ToString(), documentList[0].ProjectId));
var pushStreamContent = new PushStreamContent(async (outputStream, httpContent, transportContext) =>
{
//zip the multiple files
using (var zipEntry = new ZipArchive(outputStream, ZipArchiveMode.Create, leaveOpen: false))
{
for (int docId = 0; docId < documentList.Count; docId++)
{
blob = directory.GetBlockBlobReference(DocumentNameConfigValue + documentList[docId].DocumentId);
if (!blob.Exists()) continue;
MemoryStream memStream = new MemoryStream();
await blob.DownloadToStreamAsync(memStream);
memStream.Position = 0;
var createEntry = zipEntry.CreateEntry(documentList[docId].FileName, CompressionLevel.Fastest);
using (var stream = createEntry.Open())
{
memStream.CopyTo(stream);
}
}
}
});
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