根据面包屑级别动态获取页面链接

Question

我正在尝试通过 PHP 创建一个面包屑菜单，到目前为止有以下内容：<?php// 1. Get URL$crumbs = explode("/",$_SERVER["REQUEST_URI"]);$address = 'http://'.$_SERVER['HTTP_HOST'];// 2. Strip extrasforeach($crumbs as $crumb){    $crumb = ucfirst(str_replace(array(".php","_"),array(""," "),$crumb) . ' ');    echo "<a href=".$address.">"."<span class='crumbMenu'>".$crumb."</span></a>";}?>假设我有以下页面层次结构： Products > Products Level 2 > Products Level 3上面的代码会吐出：ProductsProducts Level 2Products Level 3哪个是正确的。但是，链接不是。阅读完HTTP_HOST 后，我确定我的方法是错误的，但不确定我可以采取哪些其他方法来动态获取每个面包屑项目链接？我得到的链接：localhost:8080我期待的链接：产品:/products产品 2 级：/products/products-level-2产品等级 3 :/products/products-level-2/products-level-3

Answer 1

您似乎忘记了向$address变量添加路由，因此所有面包屑都指向基本服务器地址。请尝试以下操作：

<?php

// 1. Get URL

$crumbs = explode("/",$_SERVER["REQUEST_URI"]);

$address = 'http://'.$_SERVER['HTTP_HOST'];

// 2. Strip extras

$build = $address.'/products';

foreach($crumbs as $crumb){

    if(in_array($crumb, [$_SERVER['HTTP_HOST'], 'products'])) {

        continue;

    }

    $build .= '/'.$crumb;

    $crumb = ucfirst(str_replace(array(".php","_"),array(""," "),$crumb) . ' ');

    echo "<a href=".$address.$build.">"."<span class='crumbMenu'>".$crumb."</span></a>";

}

?>

Answer 2

准备好您的回声非常困难，这没有帮助。我创建了一个小函数，它应该可以满足您的要求。随意修改它以满足您的需要。

$crumbs = "/x/y/z";

$address = "localhost:8080";

$crumbs = explode('/', $crumbs);

$end = '';

$href = '';

foreach ($crumbs as $crumb) {

    $crumb = str_replace('.php', '', $crumb);

    $end .= $crumb . ' ';

    $href .= $crumb . '/';

}

echo("HREF => " . $href);

echo("\n");

echo("TITLE => " . $end);