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TA贡献1943条经验 获得超7个赞
说明:
你的错误的原因是sqlsrv_query() return false,这意味着你的语句没有正确执行:
返回值(sqlsrv_query):
语句资源。如果无法创建和/或执行该语句,则返回 false。
如果语句未正确执行,您需要检查 的结果sqlsrv_query()并获取错误sqlsrv_errors()。
<?php
...
$query = sqlsrv_query($conn, $sql, array(), array("Scrollable" => SQLSRV_CURSOR_KEYSET));
if ($query === false) {
echo "Error (sqlsrv_query): ".print_r(sqlsrv_errors(), true);
exit;
}
...
?>
补充说明:
尝试使用参数化查询。函数sqlsrv_query()支持使用参数:
sqlsrv_query 函数非常适合一次性查询,除非特殊情况适用,否则应该是执行查询的默认选择。此函数提供了一种以最少代码执行查询的简化方法。sqlsrv_query 函数同时进行语句准备和语句执行,并可用于执行参数化查询。
示例(基于您的代码):
<?php
if (!isset($_POST['referenceno'])) {
echo "Error."
exit;
}
$data = $_POST['referenceno'];
//$user = $user['fingerscanno'];
$explode = explode(":", $data);
$deptcode = $explode[0];
$emp = $explode[1];
$empno = str_pad(++$emp, 7, "0", STR_PAD_LEFT);
$jobposition = $explode[2];
$departmentname = $explode[3];
$sql = "
SELECT
DISTINCT LEFT (departmentcode,4) as deptcode,
MAX(RIGHT(employeeidno, 7)) as empno,
section,
departmentname,
paymentmode,
hrdjobpositionentry.jobposition as jobposition
FROM departmentmasterfile, hrdjobpositionentry,employeemasterfile
WHERE
hrdjobpositionentry.department = departmentmasterfile.departmentname AND
LEFT (employeemasterfile.employeeidno,4) = LEFT (departmentmasterfile.departmentcode,4) AND
LEFT (departmentcode,4) = ? AND hrdjobpositionentry.jobposition = ?
GROUP BY LEFT (departmentcode,4), section, departmentname, paymentmode, hrdjobpositionentry.jobposition
ORDER BY LEFT (departmentcode,4);
INSERT INTO employeemasterfile (employeeidno) VALUES (? + ?);
";
$params = array(
$deptcode,
$jobposition,
$deptcode,
$empno
);
$query = sqlsrv_query($conn, $sql, $params, array("Scrollable" => SQLSRV_CURSOR_KEYSET));
if ($query === false) {
echo "Error (sqlsrv_query): ".print_r(sqlsrv_errors(), true);
exit;
}
while($row = sqlsrv_fetch_array($query, SQLSRV_FETCH_ASSOC)) {
var_dump($row);
echo "<br>";
}
sqlsrv_free_stmt($query);
?>
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