合并共享相同 ID 的数组

Question

目前我有这样的JSON：[  {    "user_id": 6,    "room_id": 2,    "date_from": "2019-09-15 00:00:00",    "date_to": "2020-09-01 00:00:00",    "created_at": null,    "updated_at": null,    "users": [      {        "id": 6,        "name": "Makenna",        "surname": "Boyle",        "email": "[e-mail]",        "university_id": 3      }    ],    "room": {      "id": 2,      "room_number": 327,      "floor": 3,      "slots": 2,      "dorm_id": 1,      "price": 0,      "features": "[{\"feature\":\"Nemokamas WiFi\",\"feature\":\"Erdvus dušas\"}]",      "photos": "[{\"img\":\"\\/images\\/rooms\\/9_1_5d3f6735884627.19832875.jpg\"},{\"img\":\"\\/images\\/rooms\\/9_1_5d3f673589a070.51161328.jpg\"},{\"img\":\"\\/images\\/rooms\\/9_1_5d3f67358b0419.09559739.jpg\"}]",      "created_at": null,      "updated_at": null,      "dorm": {        "id": 1,        "name": "Statybininkų prospekto bendrabutis",        "university_id": 2,        "photo": "https://www.umt.edu/housing/rh/descriptions/photos/Miller%20West%20Side%20View.jpg",        "university": {          "id": 2,          "name": "Klaipėdos Universitetas",          "city": "Klaipėda"        }      }    }  },  {    "user_id": 8,    "room_id": 2,    "date_from": "2019-09-15 00:00:00",    "date_to": "2020-09-01 00:00:00",    "created_at": null,    "updated_at": null,    "users": [      {        "id": 8,        "name": "Kassandra",        "surname": "Blick",        "email": "[e-mail]",        "university_id": 2      }    ],

Answer 1

此代码将帮助您实现目标。

$data = json_decode($json);

$newFormat = [];

foreach ($data AS $each) {

    if (!isset($newFormat[$each->room_id])) { 

        $newFormat[$each->room_id] = $each;

    } else {

        $newFormat[$each->room_id]->users[] = $each->users[0];

    }

}

echo "<pre>" . var_export($newFormat, true) . "</pre>";

这将显示您期望的确切结果