从数组中获取随机数，不重复（带定时器）

Question

您好，感谢您阅读这篇文章。我正在尝试创建一个自动 Bingo call-out-loud 数字游戏，但我一直在控制台日志中未定义。有任何想法吗？我有一个数组，这些项目需要随机调用，不要重复，当完成时停止并说“结束”或“完成”之类的东西。非常感谢！var nums = ["one","two","three","four","five","six","seven","eight","nine","ten"],ranNums = [],i = nums.length,j = 0;setInterval(getNum,2000);function getNum(){  j = Math.floor(Math.random() * (i+1));  ranNums.push(nums[j]);  nums.splice(j,1);  console.log(ranNums[ranNums.length-1]);}

Answer 1

问题在于，一旦拼接数组，您就不会修改 'i' 变量。

例如，您的阵列最终可能会变成

nums = ["one","two","three","four","ten"]

虽然你的 'i' 仍然是 10，所以 'j' 可以获得对你的数组来说太大的值，从而导致你未定义。

为了解决这个问题，让 'i' 获得新的数组长度或在函数结束时将其减少 1

Answer 2

我希望这会帮助你 :)

var nums = ["one","two","three","four","five","six","seven","eight","nine","ten"],

ranNums = [],

j = 0;

intervall = setInterval(getNum,2000);

  function getNum(){

  

    i = nums.length

    

    if(i == 0) {

      clearInterval(intervall)

      console.log('the end')

    } else {

        console.log(i)

        j = Math.floor(Math.random() * (i));

        ranNums.push(nums[j]);

        nums.splice(j,1);

        console.log(ranNums[ranNums.length-1]);

      }

   }

Answer 3

首先 splice() 方法通过删除或替换现有的来改变数组的内容。Splice 这就是为什么你没有定义（因为你修改了初始数组长度。另外，如果你稍微搜索一下，你会发现在两个值之间获取一个随机整数

你也没有提到你什么时候想停下来。但下面是宾果游戏！！！

var nums = ["one", "two", "three", "four", "five", "six", "seven", "eight", "nine", "ten"],

  ranNums = [],

  i = nums.length,

  j = 0;

setInterval(getNum2, 2000);

function getNum2() {

  var min = Math.ceil(null); //rounds a number up to the next largest whole number or integer

  var max = Math.floor(nums.length); // returns the largest integer less than or equal to a given number

  var rdNumber = Math.floor(Math.random() * (max - min)) + min;

  // You can set a rult when you want to stop for e.g 

  // if (ranNums.length === 5){ clearInterval(getNum2)}

  ranNums.push(nums[rdNumber]);

  console.log(nums[rdNumber]);

}