在 Java 中用字符串重复整个循环很困难

Question

我是编程新手，我开始练习 Java。在我的练习中，我要求编写一个程序来计算并打印出一个数字的数字之和。然后它打印出和数的所有除数。问题是在那之后，我需要问用户他们是否想尝试另一个号码，并且当这个人回答“是”时我无法重新启动程序。谢谢你，对不起我的英语！//Introduction        System.out.println("\nWelcome to our Calculation Program!\n----------------------------------------");        System.out.print("Enter a number with at most 7-digits:");        int input = mykeyboard.nextInt();        int sum = 0;        while (input > 0) {            int add = input % 10;            sum = sum + add;            input = input / 10;        }        System.out.println("Sum of the digits of your input is: " + sum);        System.out.print("The divisors of " + sum + " are as follows: " );        for (int counter = 1; sum >= counter; counter++) {            if (sum % counter == 0)        System.out.print(counter + " ");    }         System.out.println("\n\nDo you want to try another number?");        Scanner mykeyboard2 = new Scanner(System.in);        String choice = mykeyboard2.nextLine();        if (choice.equals("yes")) {            System.out.println("Enter a number with a most 7-digits:");            while (input > 0);                int add = input % 10;                sum = sum + add;                input = input / 10;                System.out.println("Sum of the digits of your input is: " + sum);                System.out.print("The divisors of " + sum + " are as follows: " );                for (int counter = 1; sum >= counter; counter++)                    if (sum % counter == 0)                        System.out.print(counter + " ");} if (choice.equals("no")) {System.out.println("Thanks and Have a Great Day!");

Answer 1

while (input > 0);

这将进入无限循环。我想你把一个;而不是{.

应该 while (input > 0){

编辑：

System.out.println("\nWelcome to our Calculation Program!\n----------------------------------------");

while(true){

    System.out.print("Enter a number with at most 7-digits:");

    int input = mykeyboard.nextInt();

    int sum = 0;

    while (input > 0) {

        int add = input % 10;

        sum = sum + add;

        input = input / 10;

    }

    System.out.println("Sum of the digits of your input is: " + sum);

    System.out.print("The divisors of " + sum + " are as follows: " );

    for (int counter = 1; sum >= counter; counter++) {

        if (sum % counter == 0)

        System.out.print(counter + " ");

    } 

    System.out.println("\n\nDo you want to try another number?");

    Scanner mykeyboard2 = new Scanner(System.in);

    String choice = mykeyboard2.nextLine();

    if (choice.equals("no")) {

        break;

    }

}

Answer 2

实现它的最简单方法是使用您的选择变量来控制循环条件：

System.out.println("\nWelcome to our Calculation Program!\n----------------------------------------");

String choice = "yes";

while(choice.equals("yes")) {

    System.out.print("Enter a number with at most 7-digits:");

    int input = mykeyboard.nextInt();

    int sum = 0;

    while (input > 0) {

        int add = input % 10;

        sum = sum + add;

        input = input / 10;

    }

    System.out.println("Sum of the digits of your input is: " + sum);

    System.out.print("The divisors of " + sum + " are as follows: " );

    for (int counter = 1; sum >= counter; counter++) {

        if (sum % counter == 0)

    System.out.print(counter + " ");

    System.out.println("\n\nDo you want to try another number?");

    Scanner mykeyboard2 = new Scanner(System.in);

    choice = mykeyboard2.nextLine();

}

System.out.println("Thanks and Have a Great Day!");

Answer 3

你只需要让循环重新开始

        System.out.print("Enter a number with at most 7-digits:");

    int input = mykeyboard.nextInt();

    while(input != -1){

    int sum = 0;

        int add = input % 10;

        sum = sum + add;

        input = input / 10;

    System.out.println("Sum of the digits of your input is: " + sum);

    System.out.print("The divisors of " + sum + " are as follows: " );

    for (int counter = 1; sum >= counter; counter++) {

        if (sum % counter == 0)

    System.out.print(counter + " ");

    System.out.print("Do you want another number? If you dont type -1: ");

    input = mykeyboard.nextInt();

    }

代码会一直运行直到用户输入 -1