我有以下xml“文件”:<pinnacle_line_feed> <PinnacleFeedTime>1439954818555</PinnacleFeedTime> <lastContest>34317132</lastContest> <lastGame>218491030</lastGame> <events> <event> <event_datetimeGMT>2015-08-21 09:50</event_datetimeGMT> <gamenumber>483406220</gamenumber> <sporttype>Aussie Rules</sporttype> <league>AFL</league> <IsLive>No</IsLive> <participants> <participant> <participant_name>Hawthorn Hawks</participant_name> <contestantnum>1251</contestantnum> <rotnum>1251</rotnum> <visiting_home_draw>Visiting</visiting_home_draw> </participant> <participant> <participant_name>Port Adelaide Power</participant_name> <contestantnum>1252</contestantnum> <rotnum>1252</rotnum> <visiting_home_draw>Home</visiting_home_draw> </participant> </participants> <periods></periods> </event> </events></pinnacle_line_feed>我试图用 Golang 解析这个,到目前为止已经写了以下内容:package mainimport ( "fmt" "encoding/xml")type Participant struct { XMLName xml.Name `xml:"participant"` participant_name string `xml:"participant_name"` contestantnum int `xml:"contestantnum"` rotnum int `xml:"rotnum"` visiting_home_draw string `xml:"visiting_home_draw"`}坦率地说,我对 Golang 中的深度嵌套 xml 解析研究了很多,但我没有找到太多可以帮助解决此代码的 Unmarshal 部分的问题。理想情况下,代码将返回类似于 Python 字典的内容,例如,{event_datetimeGMT: 2015-08-21, gamenumber: 483406220, ... ,visiting_home_draw: "Home"}
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