如何解决函数调用中不断变化的指针值？这是一个cgo错误吗？

Question

我这样通过 cgo 调用 C 函数：var _outptr_7 C.double var _outptr_8 C.double  var kk uintptr = uintptr(unsafe.Pointer(&_outptr_7))gogsl.InitializeGslFunction(f)_result := int32(C.gsl_integration_qags((*C.gsl_function)(unsafe.Pointer(f.CPtr())), C.double(a), C.double(b), C.double(epsabs), C.double(epsrel), C.size_t(limit), (*C.gsl_integration_workspace)(unsafe.Pointer(workspace.Ptr())), (*C.double)(&_outptr_7), (*C.double)(&_outptr_8)))fmt.Printf("%10.10X\n",kk)return _result, *(*float64)(unsafe.Pointer(&_outptr_7)), *(*float64)(unsafe.Pointer(&_outptr_8))现在，kk这里用于调试目的。我修改了 C 函数gsl_integration_qags以输出它收到的第 8 个参数（即&_outptr_7，_<n>从 0 开始的计数！）（InitializeGslFunction出于此处的目的可以忽略...）这两个值 -kk以及 C 函数输出 - 完全匹配。但是，我得到的数字与 C 函数返回的数字不同- 它通过间接方式设置第 8 个参数。我确定这是正确的，我看过它在 gdb 中工作。它看起来像这样：（省略了(gdb)我点击回车重复命令的地方）Breakpoint 3, qags (f=0xc20800a260, a=0, b=1, epsabs=0, epsrel=9.9999999999999995e-08, limit=1000, workspace=0x782ec0, result=0xc208031e28, abserr=0xc208031e20, q=0x7ffff79ad12c <gsl_integration_qk21>) at qags.c:479479   *result = res_ext;(gdb) n480   *abserr = err_ext;(gdb) p *result$1 = -4.0000000000000853(gdb) p result$2 = (double *) 0xc208031e28(gdb) n482   if (err_ext == GSL_DBL_MAX)485   if (error_type || error_type2)513     double max_area = GSL_MAX_DBL (fabs (res_ext), fabs (area)); 515     if (!positive_integrand && max_area < 0.01 * resabs0)520     double ratio = res_ext / area;522     if (ratio < 0.01 || ratio > 100.0 || errsum > fabs (area))526   goto return_error;535   if (error_type > 2) 540   if (error_type == 0) 542       return GSL_SUCCESS;573 }gsl_integration_qags (f=0xc20800a260, a=0, b=1, epsabs=0, epsrel=9.9999999999999995e-08, limit=1000, workspace=0x782ec0, result=0xc208031e28, abserr=0xc208031e20) at qags.c:5353    return status ;54  }