Angular 如何检查 2 个数组中的重叠值？

Question

我想检查 2 个数组中的重叠值场景一：cuisineA = [a,b,c];cuisineB = [a,b,c,d,e,f];将返回一个布尔值isOverlap = true场景2：cuisineA = [a,b,c];cuisineB = [d,e,f];将返回一个布尔值isOverlap = false目前我的代码看起来像这样const overlapCuisines = this.cuisineA.filter(      cuisine => this.cuisineB.indexOf(cuisine) < 0    );this.isOverlap = overlapCuisines.length > 0;然而，当它在场景 2 中时，overlapCuisines 将包含值 [a,b,c]，因此 isOverlap = true 当它应该是 false 时。我应该如何编码以正确显示它？感谢你的帮助！

Answer 1

使用集合交集

let isOverlap = !!((new Set(A)).intersection(new Set(B)))

注意：这是伪代码

Answer 2

如果项目的顺序不重要，则可以使用Array.some()方法。

var cuisineA = ["a","b","c"];

var cuisineB = ["a","b","c","d","e","f"];

var isOverlap = cuisineA.some(value => cuisineB.includes(value));

console.log(isOverlap);

cuisineA = ["a","b","c"];

cuisineB = ["d","e","f"];

isOverlap = cuisineA.some(value => cuisineB.includes(value));

console.log(isOverlap);

Answer 3

尝试这样的事情。

const overlapCuisines = this.cuisineA.filter(cuisine => this.cuisineB.indexOf(cuisine) !== -1);

this.isOverlap = overlapCuisines.length > 0 ? true : false;

或者

this.isOverlap = Boolean(overlapCuisines.length > 0) ;