Puppeteer 从 Node 中监听 map.on('load')

Question

使用 Puppeteer 从 Node 中监听 map.on('load')。(async () => {  const browser = await puppeteer.launch({ headless: false, devtools: true });  const page = await browser.newPage();  function nodeLog(msg) {    console.log(msg);  }  page.on('load', async () => {    await page.evaluate(() => {      window.map.on('load', () => {        console.log("This runs on the index.html js but I do not need that");        nodeLog("WHY IS THIS NOT WORKING??")      })    })  });  await page.goto(`file:${__dirname + '/index.html'}`);})();

Answer 1

我还想出了如何返回信息。我重读了文档并得到了一些理解。我不理解上下文。

const nodeLog = msg => console.log;

const msg = await page.evaluate(() => { return 'this is working' });

nodeLog(msg);