如何使用 XPath 读取 xlink:label 值

Question

我需要从 XML 获取 xlink:label 值（ASSET_1）。<MESSAGE xmlns:xlink="http://www.w3.org/1999/xlink"><ABOUT_VERSIONS><ABOUT_VERSION SequenceNumber="1"  xlink:label="ASSET_1" ><CreatedDatetime>2015-08-24T09:30:47Z</CreatedDatetime><DataVersionName>Purchase Example</DataVersionName></ABOUT_VERSION></ABOUT_VERSIONS></MESSAGE>我正在尝试的 Java 代码如下所示XPathFactory xpf = XPathFactory.newInstance();            XPath xPath = xpf.newXPath();XPathExpression pathExpression = xPath.compile("MESSAGE/ABOUT_VERSIONS/ABOUT_VERSION");   InputSource inputSource = new InputSource("C:/Sample.xml");  NodeList Nodes = (NodeList) xPath.evaluate("MESSAGE/ABOUT_VERSIONS/ABOUT_VERSION", inputSource, XPathConstants.NODESET);System.out.println("SequenceNumber:: "+xPath.evaluate("MESSAGE/ABOUT_VERSIONS/ABOUT_VERSION/@SequenceNumber", inputSource, XPathConstants.NODE));System.out.println(" "+xPath.evaluate("MESSAGE/ABOUT_VERSIONS/ABOUT_VERSION/@xlink:label", inputSource, XPathConstants.NODE));OutPutSequenceNumber:: SequenceNumber="1"null我在提取 xlink:label 的值时犯了什么错误？请帮忙。

Answer 1

您可以使用@*[name()='xlink:label']代替@xlink:label. 也切换到@*[local-name()='label']应该可以解决问题。