如何打印getter String而不将null作为输出？

Question

每当我使用 showMessage() 时，我都会得到空值；我相信这是因为我在方法结束时返回了 c 。有没有办法打印出 getName() 而不是在 main 方法中，就像 getName() 在 showMessage() 方法中一样。. 这是我的候选人类public class Candidate {private String name;private int votes;//default constructorpublic Candidate() {String name = "Not Available! ";int votes = 0; }//overloaded constructorpublic Candidate(String _name, int _votes){  name  = _name;  votes = _votes;}//getterpublic String getName(){return name;}public int getVotes(){return votes;}//setterpublic void incrementVote(){  votes = votes + 1;}public void setName(String _name){    name =_name;}public void print(){    System.out.println("To vote for " + name);}}这是我的主要import java.util.*;public class Election {public static void main(String args[]){System.out.println("Welcome to the polls! "); Candidate c1 = new Candidate(); Candidate c2 = new Candidate(); Candidate c3 = new Candidate(); Candidate c4 = new Candidate();c1 = inputCandidate();c2 = inputCandidate();c3 = inputCandidate();c4 = inputCandidate();c1 = showMessage();}private static Candidate inputCandidate(){    Scanner sc = new Scanner(System.in);    String inputN;    Candidate c = new Candidate();    System.out.println("Enter candidate");    inputN = sc.nextLine();    c.setName(inputN);   return c;}private static Candidate showMessage(){    Candidate c = new Candidate();    System.out.println(c.getName());    return c;}}

Answer 1

只需更换

c1 = showMessage();

和，

showMessage(c1);

并修改方法showMessage如下

private static void showMessage(Candidate c ){    

    System.out.println(c.getName());

}

同样，您可以使用showMessage打印剩余对象的消息，例如

showMessage(c2);

showMessage(c3);

showMessage(c4);