我有一个 d3 可视化，它有一个类似于以下的 JSON 对象，我想平均score最低节点上的值，并将该平均值动态添加到上面的父节点......等等。看起来 d3 没有一个简单的方法来做到这一点。我想要的是让最终的 JSON 输出看起来像第二个例子。 { "name": "A1", "children": [ { "name": "B1", "children": [ { "name": "B1-C1", "children": [ { "name": "B1-C1-D1", "children": [ { "name": "B1-C1-D1-E1", "value": 30, "score": 0.8 }, { "name": "B1-C1-D1-E2", "value": 35, "score": 0.5 } ] }, { "name": "B1-C1-D2", "children": [ { "name": "B1-C1-D2-E1", "value": 31, "score": 0.4 }, { "name": "B1-C1-D2-E2", "value": 23, "score": 0.7 } ] } ] } ] } ]}我希望最终的 JSON 对象看起来像：{ "name": "A1", "scoreAvg": 0.625, "children": [ { "name": "B1", "scoreAvg": 0.625, "children": [ { "name": "B1-C1", "scoreAvg": 0.625, "children": [ { "name": "B1-C1-D1", "scoreAvg": 0.7, "children": [ { "name": "B1-C1-D1-E1", "value": 30, "score": 0.8 }, { "name": "B1-C1-D1-E2", "value": 35, "score": 0.6 } ] }, { "name": "B1-C1-D2", "scoreAvg": 0.55, "children": [ { "name": "B1-C1-D2-E1", "value": 31, "score": 0.4 },
2 回答
蝴蝶不菲
TA贡献1810条经验 获得超4个赞
let o = {
"name": "A1",
"children": [
{
"name": "B1",
"children": [
{
"name": "B1-C1",
"children": [
{
"name": "B1-C1-D1",
"children": [
{
"name": "B1-C1-D1-E1",
"value": 30,
"score": 0.8
},
{
"name": "B1-C1-D1-E2",
"value": 35,
"score": 0.5
}
]
},
{
"name": "B1-C1-D2",
"children": [
{
"name": "B1-C1-D2-E1",
"value": 31,
"score": 0.4
},
{
"name": "B1-C1-D2-E2",
"value": 23,
"score": 0.7
}
]
}
]
}
]
}
]
};
function avgUp(object){
object.avgScore = 0;
if(object.children){
for(child of object.children){
object.avgScore += avgUp(child);
}
object.avgScore = object.avgScore /Math.max(1,object.children.length);
return object.avgScore;
}else{
return object.score;
}
}
avgUp(o);
console.log(JSON.stringify(o));
红糖糍粑
TA贡献1815条经验 获得超6个赞
您可以使用递归函数：
const obj = {
"name": "A1",
"children": [{
"name": "B1",
"children": [{
"name": "B1-C1",
"children": [{
"name": "B1-C1-D1",
"children": [{
"name": "B1-C1-D1-E1",
"value": 30,
"score": 0.8
},
{
"name": "B1-C1-D1-E2",
"value": 35,
"score": 0.5
}
]
},
{
"name": "B1-C1-D2",
"children": [{
"name": "B1-C1-D2-E1",
"value": 31,
"score": 0.4
},
{
"name": "B1-C1-D2-E2",
"value": 23,
"score": 0.7
}
]
}
]
}]
}]
}
function getWithAverageScore(objToRecurse) {
// If I have a score I am already done
if (objToRecurse.score) {
return objToRecurse;
}
// Otherwise, I get my children with their average score
const children = objToRecurse.children.map(getWithAverageScore);
return {
...objToRecurse,
children,
// And I set my scoreAvg to their average (score or scoreAvg)
scoreAvg: children.reduce((total, { score, scoreAvg }) => total + (score || scoreAvg), 0) / children.length
};
}
console.log(JSON.stringify(getWithAverageScore(obj), null, 2))
添加回答
举报
0/150
提交
取消