如何在单人游戏的文本文件中为前 5 名玩家创建一个简单的有序排行榜

Question

我正在做一个 1 名球员测验，需要实施一个高分系统，记录前 5 名高分球员的分数和适合该得分球员的球员姓名。这应该写入文本文件 (.txt) 并在分数更高时覆盖（从 1. 最高分到 5. 最低分排序）。如果有人可以分享一些我可以用于我的高分系统的代码，那将非常有帮助。通过 n 轮的玩家应该从最高 n 分到最低 n 分排序。它应该在 txt 文件中包含前 5 个 n 分数，并按顺序排列。我已经看了几个小时的论坛，但无法在我的代码中实现我发现的代码。旁注：我根本不知道该怎么做counter = 0print("The songs' initials are " ,initialsofsong, " and the name of the artist is " ,randomartist)print (randomsong)songnameguess = input("Guess the name of the song!")counter = counter + 1while counter < 3 and songnameguess != randomsong :        songnameguess = input("Nope! Try again!")        counter = counter + 1if songnameguess == randomsong:    print ("Well done!")    if counter == 2:        score = score + 1    elif counter == 1:        score = score + 3elif counter >=3 and songnameguess != randomsong:    print ("Sorry, you've had two chances. Come back soon!")    print ("Game over.")    print (score)

Answer 1

您可以以多种格式存储分数，我将使用json，因为它是可读且内置的：

score_file = r"/pat/to/score/file.json"

# at the beginning of your script: load the current scores

try:

    with open(score_file, 'r') as f:

        scores = json.load(f)

except FileNotFoundError:

    scores = {}

# (...)

# during your script: update the scores with the player's new

scores[player_name] = new_score

# (...)

# at the end of your script: store the new scores

with open(score_file, 'w+') as f:

    json.dump(scores, f)

打印你的分数排序：

scores_sorted = sorted([(p, s) for p, s in scores.items()], reverse=True, key=lambda x: x[1])

for player, score in scores_sorted:

    print(player, score)