我似乎无法弄清楚为什么要这样做:我有一个这样的功能设置:func (srv *Server) StartServer() { // Some stuff to make sure paths are correct path := srv.Path + "server.exe" var args = []string{ "ip=" + srv.IP, "un=" + srv.Username, "pw=" + srv.Password } proc, err := os.StartProcess(path, args, new(os.ProcAttr)) if err != nil { panic(err) }}StartProcess 方法抛出一个超出范围的索引。我可能只是错过了一些东西,但我就是看不到它。要求的确切错误:panic: runtime error: index out of rangegoroutine 1 [running]:syscall.StartProcess(0xc082052b70, 0x21, 0xc08200a6e0, 0x5, 0x5, 0xc08201dd60, 0x0, 0x0, 0x0, 0x0) c:/go/src/syscall/exec_windows.go:322 +0x94cos.startProcess(0xc082052b70, 0x21, 0xc08200a6e0, 0x5, 0x5, 0xc08200a730, 0x5217e0, 0x0, 0x0) c:/go/src/os/exec_posix.go:45 +0x482os.StartProcess(0xc082052b70, 0x21, 0xc08200a6e0, 0x5, 0x5, 0xc08200a730, 0x0, 0x0, 0x0) c:/go/src/os/doc.go:24 +0x79main.(*Server).StartServer(0x5efae0) E:/build_test/SrvMgr.go:85 +0x4e6main.main() E:/build_test/SrvMgr.go:54 +0x141goroutine 2 [runnable]:runtime.forcegchelper() c:/go/src/runtime/proc.go:90runtime.goexit() c:/go/src/runtime/asm_amd64.s:2232 +0x1goroutine 3 [runnable]:runtime.bgsweep() c:/go/src/runtime/mgc0.go:82runtime.goexit() c:/go/src/runtime/asm_amd64.s:2232 +0x1goroutine 4 [runnable]:runtime.runfinq() c:/go/src/runtime/malloc.go:712runtime.goexit() c:/go/src/runtime/asm_amd64.s:2232 +0x1exit status 2编辑:链接到重现它的简化 play.golang 帖子。我正在运行 go version 1.4.2 win/amd64http://play.golang.org/p/S6kRLMyd2I
1 回答
FFIVE
TA贡献1797条经验 获得超6个赞
您收到错误是因为您没有在 os.ProcAttr 上设置 Stderr 和 Stdout 的文件描述符。似乎这些会在 linux 上自动设置,但您需要在 Windows 上设置它们。
这是一个工作示例:
func (srv *Server) StartServer() {
// Some stuff to make sure paths are correct
path := srv.Path + "server.exe"
var args = []string{
"ip=" + srv.IP,
"un=" + srv.Username,
"pw=" + srv.Password
}
var attr os.ProcAttr
attr.Files = []*os.File{nil, os.Stdout, os.Stderr}
proc, err := os.StartProcess(path, args, &attr)
if err != nil {
panic(err)
}
}
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