我有一个表格,我可以从中上传一些文件。文件数组显示正确print,但目标文件夹中没有文件。我错过了什么?这是我的代码:// Fileuploadif (!is_dir('../incidentbijlagen/'.$inc['incident']['companyname'].'')) { mkdir('../incidentbijlagen/'.$inc['incident']['companyname'].'', 0777, true);}$uploads_dir = '../incidentbijlagen/'.$inc['incident']['companyname'].'/';foreach($bijlage['incident'] as $key => $file){ $tmp_name = $file['incident']['tmp_name']['bijlage'][$key]; $name = basename($file['incident']['name']['bijlage'][$key]); move_uploaded_file($tmp_name, "$uploads_dir/$name");}我的 error_log 中没有错误,所以我不确定为什么文件没有被移动。这是我的阵列在我print它时的样子:Array( [incident] => Array ( [name] => Array ( [bijlage] => Array ( [0] => fblogosnm.jpg ) ) [type] => Array ( [bijlage] => Array ( [0] => image/jpeg ) ) [tmp_name] => Array ( [bijlage] => Array ( [0] => /tmp/phpnh5aHW ) ) [error] => Array ( [bijlage] => Array ( [0] => 0 ) ) [size] => Array ( [bijlage] => Array ( [0] => 20573 ) ) ))
2 回答
慕桂英546537
TA贡献1848条经验 获得超10个赞
摆脱循环并尝试使用 0 像这样:
$tmp_name = $file['incident']['tmp_name']['bijlage'][0];
$name = basename($file['incident']['name']['bijlage'][0]);
move_uploaded_file($tmp_name, "$uploads_dir/$name");
更新
好多个,试试这个:
foreach($bijlage['incident']['name']['bijlage'] as $key => $file) {
$tmp_name = $file['incident']['tmp_name']['bijlage'][$key];
move_uploaded_file($tmp_name, "$uploads_dir/$file");
}
HUX布斯
TA贡献1876条经验 获得超6个赞
尝试替换: $uploads_dir = '../incidentbijlagen/'.$inc['incident']['companyname'].'/';
和: $uploads_dir = realpath('../incidentbijlagen/'.$inc['incident']['companyname'].'/');
这将返回完整路径(例如:/var/www/yourwebsite/incidentbijlagen/ 等)
- 2 回答
- 0 关注
- 187 浏览
添加回答
举报
0/150
提交
取消