我已经使用 JQuery 很长时间了,我熟悉其中的 AJAX-Calls。我经常遇到这样的情况,我必须等到多个请求完成后才能继续获得结果。JQuery 语法如下: $.when( $.ajax({ type: "POST", url: '/Services/Service.asmx/GetResults1', contentType: "application/json; charset=utf-8", dataType: "json", success: function (msg) { ... }, error: function (e) { console.log('ERROR! ' + e.responseText); } }), $.ajax({ type: "POST", url: '/Services/Service.asmx/GetResults2', contentType: "application/json; charset=utf-8", dataType: "json", success: function (msg) { ... }); }, error: function (e) { console.log('ERROR! ' + e.responseText); } }) ).done(function (result1, result2) { // Do s.th. with result1 and result2 what is already // available here updateUI(); ... });你怎么能在 VanillaJS 中做到这一点?
2 回答
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慕斯709654
TA贡献1840条经验 获得超5个赞
将此与您的 AJAX 请求进行比较:
var xhttp = new XMLHttpRequest();
xhttp.onreadystatechange = function() {
if (this.readyState == 4 && this.status == 200) {
receivedJSON = JSON.parse(xhttp.responseText);
//Your success: function here...
}else{
//Your error: function here...
}
};
xhttp.open("POST","/Services/Service.asmx/GetResults1",true);
xhttp.send(/**Your JSON Data**/);
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