如何根据条件将元素连接到同一列表中的其他元素

Question

我有一个项目清单：例如：a = ['when', '#i am here','#go and get it', '#life is hell', 'who', '#i am here','#go and get it',]我想根据条件合并列表项，即合并所有项目，直到该项目在第一个位置具有 # 并将其替换为 when 或 who。我想要的输出是：['when', 'when i am here','when go and get it', 'when life is hell', 'who', 'who i am here','who go and get it',]

Answer 1

您可以迭代a，如果单词不是以 开头，则保存该单词，如果是'#'，则替换'#'为保存的单词：

for i, s in enumerate(a):

    if s.startswith('#'):

        a[i] = p + s[1:]

    else:

        p = s + ' '

a 变成：

['when', 'when i am here', 'when go and get it', 'when life is hell', 'who', 'who i am here', 'who go and get it']

Answer 2

只需关闭您提供的信息，您就可以做到这一点。

    a = ['when', '#i am here','#go and get it', '#life is hell', 'who', '#i am here','#go and get it']

    whoWhen = ""                                                 #are we adding 'who or when'

    output = []                                                  #new list

    for i in a:                                                  #loop through

        if " " not in i:                                         #if there's only 1 word

            whoWhen = i + " "                                    #specify we will use that word

            output.append(i.upper())                             #put it in the list

        else:                           

            output.append(i.replace("#", whoWhen))               #replace hashtag with word

    print(output)

印刷：

['WHEN', 'when i am here', 'when go and get it', 'when life is hell', 'WHO', 'who i am here', 'who go and get it']

Process returned 0 (0x0)        execution time : 0.062 s

Press any key to continue . . .

Answer 3

干得好：

def carry_concat(string_list):

    replacement = ""  # current replacement string ("when" or "who" or whatever)

    replaced_list = []  # the new list

    for value in string_list:

        if value[0] == "#":

            # add string with replacement

            replaced_list.append(replacement + " " + value[1:])

        else:

            # set this string as the future replacement value

            replacement = value

            # add string without replacement

            replaced_list.append(value)

    return replaced_list

a = ['when', '#i am here','#go and get it', '#life is hell', 'who', '#i am here','#go and get it',]

print(a)

print(carry_concat(a))

这打印：

['when', '#i am here', '#go and get it', '#life is hell', 'who', '#i am here', '#go and get it']

['when', 'when i am here', 'when go and get it', 'when life is hell', 'who', 'who i am here', 'who go and get it']