为什么通过合并其他属性创建的实例属性不会改变，即使原始属性被覆盖

Question

我无法理解为什么即使在更改对象属性 self.name 和 self.author 之后，self.details 也会打印同一行。class Book(object):    def __init__(self, name, author):        self.name = name        self.author = author        self.details = self.name + ' written by ' + self.authorbk = Book("Harry Potter", "J K Rowling")print(bk.name)print(bk.author)print(bk.details)   #Harry Potter written by J K Rowlingbk.name = 'Becoming'bk.marks= 'Michelle Obama'print(bk.name)print(bk.author)print(bk.details)   #Harry Potter written by J K Rowling

Answer 1

因为details是从原始值创建的。连接发生后，它完全独立于其他值。如果您想要使用name/的当前值动态构造的字符串author，请使用 apropertydetails在访问时动态计算（根本不将其存储为属性）：

class Book(object):

    def __init__(self, name, author):

        self.name = name

        self.author = author

        # Don't make a `details` attribute at all

    @property

    def details(self):

        # This method is called whenever you refer to `somebook.details`

        return self.name + ' written by ' + self.author