在PHP中使用try-catch如何在不抛出异常的情况下进入finally？

Question

关于下面的代码，我怎样才能在 PHP 中不抛出异常的情况下进入finally？try {  $db = DataSource::getConnection();  if (some condition here is TRUE) {      // go to finally without throw an exception   }  $stmt = $db->prepare($sql);  $stmt->saveMyData();} catch (Exception $e) {  die($e->getMessage());} finally {  $db = null;}

Answer 1

请不要这样做，但这里有一个选项：

try {

    if (TRUE){

        goto ugh;

    }

    echo "\ndid not break";

    ugh:

} catch (Exception $e){

    echo "\ndid catch";

} finally {

    echo "\ni'm so tired";

}

我强烈建议不要使用goto. 我认为如果您使用goto.

我建议：

try {

    if (TRUE){

        echo "\nThat's better";

    } else {

       echo "\ndid not break";

    }

} catch (Exception $e){

    echo "\ndid catch";

} finally {

    echo "\ni'm so tired";

}

您只需将其余部分包装try成 anelse即可跳过它。

另一种选择是声明一个 finally 函数，调用它，然后返回。

//I'm declaring as a variable, as to not clutter the declared methods

//If you had one method across scripts, naming it `function doFinally(){}` could work well

$doFinally = function(){};

try {

    if (TRUE){

        $doFinally();

        return;

    }

    echo "\ndid not break";

} catch (Exception $e){

    echo "\ndid catch";

} finally {

    $doFinally();

}

如果您需要继续脚本，您可以声明$doFinally如下内容：

$doFinally = function($reset=FALSE){

    static $count;

    if ($reset===TRUE){

        $count = 0;

        return;

    } else if ($count===NULL)$count = 0;

    else if ($count>0)return;

}

然后在finally块之后，您可以调用$doFinally(TRUE)以将其重置为下一个try/catch