2 回答
TA贡献1735条经验 获得超5个赞
如果结构始终相同并且您想要的只是 id 值,您可以执行以下操作(在 Playground 上):
package main
import (
"fmt"
"strings"
)
func main() {
// This will work only if ids don't have spaces
fields := strings.Fields(input1)
for i, field := range fields {
if field == "id:" {
fmt.Println("Got an id: ", fields[i+1][1:len(fields[i+1])-1])
}
}
fmt.Println()
// This will extract all strings enclosed in ""
for i1, i2 := 0, 0;; {
i := strings.Index(input2[i1:], "\"") // find the first " starting after the last match
if i > 0 { // if we found one carry on
i1 = i + 1 + i1 // set the start index to the absolute position in the string
i2 = strings.Index(input2[i1:], "\"") // find the second "
fmt.Println(input2[i1 : i1+i2]) // print the string between ""
i1 += i2 + 1 // set the new starting index to after the last match
} else { // otherwise we are done
break
}
}
// Reading the text line by line and only processing port sections
parts := []string{"port{", " Entry {", " id: \"foo bar\"", " }", " Entry {", " id: \"more foo bar\"", " }", "}"}
isPortSection := false
for _, part := range parts {
if string.HasPrefix(part, "port"){
isPortSection = true
}
if string.HasPrefix(part, "host"){
isPortSection = false
}
if isPortSection && strings.HasPrefix(strings.TrimSpace(part),"id:") {
line := strings.TrimSpace(part)
fmt.Println(line[5:len(line)-1])
}
}
}
var input1 string = `port{
Entry {
id: "foo"
}
Entry {
id: "bar"
}
}`
var input2 string = `port{
Entry {
id: "foo bar"
}
Entry {
id: "more foo bar"
}
}`
印刷:
Got an id: foo
Got an id: bar
foo bar
more foo bar
您可以将它们粘贴到切片或地图中,或者做任何您想做/需要做的事情,而不是在循环中打印它们。当然,而不是使用您在文件行中读取的字符串文字。
TA贡献1874条经验 获得超12个赞
我相信text/scanner在这里可能非常有用。它不是即插即用,但允许您标记输入并很好地解析您的字符串(空格、转义值等)。概念的快速证明,带有简单状态机的扫描仪,用于捕获分段中的所有id: {str}模式Entry:
var s scanner.Scanner
s.Init(strings.NewReader(src))
// Keep state of parsing process
const (
StateNone = iota
StateID
StateIDColon
)
state := StateNone
lastToken := "" // last token text
sections := []string{} // section stack
tok := s.Scan()
for tok != scanner.EOF {
txt := s.TokenText()
switch txt {
case "id":
if state == StateNone {
state = StateID
} else {
state = StateNone
}
case ":":
if state == StateID {
state = StateIDColon
} else {
state = StateNone
}
case "{":
// Add section
sections = append(sections, lastToken)
case "}":
// Remove section
if len(sections) > 0 {
sections = sections[0 : len(sections)-1]
}
default:
if state == StateIDColon && sections[0] == "port" {
// Our string is here
fmt.Println(txt)
}
state = StateNone
}
lastToken = txt
tok = s.Scan()
}
你可以在这里玩。如果您需要验证输入结构等,这肯定需要更多的工作,但对我来说似乎是一个很好的起点。
- 2 回答
- 0 关注
- 192 浏览
添加回答
举报