(我今天早些时候遇到了类似的问题,但现在不同了)。我有一个代码来创建一个元素,为它们设置属性,最后,附加到父 div。我已经试过了:Object.entries(selectorsByProp).forEach(([prop, selector]) => { document.querySelector(selector).innerHTML = post[i][prop];});这实际上有效,但它只能操作显示和显示我的数据的元素。我需要的是它必须创建元素、设置属性和附加。这是我的可笑代码...var post = JSON.parse(this.response);for (var i = 0; i < 3; i++) { var listcard = document.createElement("div"), imgcontent = document.createElement("div"), imgcntnr = document.createElement("div"), imglnk = document.createElement("a"), a = document.createElement("a"), img = document.createElement("img"), txtcntnt = document.createElement("div"), span = document.createElement("span"); listcard.setAttribute('class', 'list-card'); imgcontent.setAttribute('class', 'img-content'); imgcntnr.setAttribute('class', 'img-container'); imglnk.setAttribute('href', '#'); img.setAttribute('class', 'thumb'); txtcntnt.setAttribute('class', 'text-content'); a.setAttribute('href', '#'); a.setAttribute('class', 'title'); span.setAttribute('class', 'excerpt'); img.setAttribute('src', post[i].img); img.setAttribute('alt', post[i].titles); a.innerHTML = post[i].titles; span.innerHTML = post[i].descs; imglnk.appendChild(img); imgcntnr.appendChild(imglnk); imgcontent.appendChild(imgcntnr); txtcntnt.innerHTML += a.outerHTML + span.outerHTML; listcard.innerHTML += imgcontent.outerHTML + txtcntnt.outerHTML; parent.appendChild(listcard);}<div class="list-card"> <div class="img-content"> <div class="img-container"> <a href="#"> <img src="https://picsum.photos/182/135/?random" alt="" class="thumb"></a> </div> </div> <div class="text-content"> <a href="#" class="title">Lorem Ipsum</a> <span class="excerpt">Lorem Ipsum</span> </div></div>
添加回答
举报
0/150
提交
取消